Answered: def aaa(p): return p ** 3 print("more…

def aaa(p): return p ** 3 print("more defs". def bbb(q): return q // 16 def ccc(p, q): print(aaa(p)) print(bbb(q)) return 1

New Perspectives on HTML5, CSS3, and JavaScript

6th Edition

ISBN:9781305503922

Author:Patrick M. Carey

Publisher:Patrick M. Carey

Chapter14: Exploring Object-based Programming: Designing An Online Poker

Section14.1: Visual Overview: Custom Objects, Properties, And Methods

Problem 7QC

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Chirality def is_left_handed(pips): Even though this has no effect on fairness, pips from one to six are not painted on dice just any which way, but so that pips on the opposite faces always add up to seven. (This convention makes it easier to tell when someone tries to use crooked dice with certain undesirable pip values replaced with values that are more desirable for the cheater.) In each of the 23 = 8 corners of the cube, exactly one value from each pair of forbidden opposites 1-6, 2-5 and 3-4 meets two values chosen from the other two pairs of opposites. You can twist and turn any corner of the die to face you, and yet two opposite sides never spread into simultaneous view. This discipline still allows for two distinct ways to paint the pips. If the numbers in the corner shared by the faces 1, 2, and 3 read out clockwise as 1-2-3, that die is left-handed, whereas if they read out as 1-3-2, that die is right-handed. Analogous to a pair of shoes made separately for the left and…
def count_odds(values): 695 >>> count_odds([[111, 165, 207]]) [3] >>> count_odds([[1, 2], [8], [5, 6, 7]]) [1,0, 2] 695
python regular expressions
Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax
Write a recursive function that returns True if the numerical array passed as input is palindrome, and False otherwise. An array is palidrome if its elements, when flipped, produce an array that is identical to the original one. For example: [1,2,3,2,1] is palindrome [1,2,3,4,3] is not palindrome Fill in the following code skeleton. It is composed of four parts: three base cases and the recursive call. Write code for all the parts. Assume that the input arrays can have any size, and that the elements are always positive integers.
kindly answer the following:
Use the template below: def createList(n): #Base Case/s #ToDo: Add conditions here for base case/s #if <condition> : #return <value> #Recursive Case/s #ToDo: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once all ToDo is completed return [] def removeMultiples(x, arr): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all ToDo return [] def Sieve_of_Eratosthenes(list): #Base Case/s if len(list) < 1 : return list #Recursive Case/s else: return [list[0]] + Sieve_of_Eratosthenes(removeMultiples(list[0], list[1:])) if __name__ == "__main__": n = int(input("Enter n: "))…
Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…
Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…
Sevens rule, zeros drool def seven_zero(n): Seven is considered a lucky number in Western cultures, whereas zero is what nobody wants to be. Let us briefly bring these two opposites together by looking at positive integers that consist of some solid sequence of sevens, followed by some (possibly empty) solid sequence of zeros. Examples integers of this form are 7, 77777, 7700000, 77777700, and 70000000000000. A surprising theorem proves that for any positive integer n, there exist infinitely many integers of such seven- zero form that are divisible by n. This function should return the smallest such seven-zero integer. Even though discrete math and number theory help, this exercise is not about coming up with a clever symbolic formula and the proof of its correctness. This is rather about iterating through the numbers of this constrained form of sevens and zeros efficiently and correctly in strictly ascending order, so that the function can mechanistically find the smallest working…
CodeWorkout Gym Course Q Search kola shreya@ columbusstate.edu Search exercises... X274: Recursion Programming Exercise: Cannonballs X274: Recursion Programming Exercise: Cannonballs Spherical objects, such as cannonballs, can be stacked to form a pyramid with one cannonball at the top, sitting on top of a square composed of four cannonballs, sitting on top of a square composed of nine. cannonballs, and so forth. Given the following recursive function signature, write a recursive function that takes as its argument the height of a pyramid of cannonballs and returns the number of cannonballs it contains. Examples: cannonball(2) -> 5 Your Answwer: 1 public int cannonball(int height) { 3. 4} Check my answer! Reset Next exercise Feedback
Bishops on a binge def safe_squares_bishops(n, bishops): A generalized n-by-n chessboard has been taken over by some bishops, each represented as a tuple (row, column) of the row and the column of the square the bishop stands on. Same as in the earlier version of this problem with rampaging rooks, the rows and columns are numbered from 0 to n - 1. Unlike a chess rook whose moves are axis-aligned, a chess bishop covers all squares that are on the same diagonal with that bishop arbitrarily far into any of the four diagonal compass directions. Given the board size n and the list of bishops on that board, count the number of safe squares that are not covered by any bishop. To determine whether two squares (r1, c1) and (r2, c2) are reachable from each other in one diagonal move, use abs(r1-r2) == abs(c1-c2) to check whether the horizontal distance between those squares equals their vertical distance, which is both necessary and sufficient for the squares to lie on the same diagonal. This…