Decrypt the message CFEJFE which was encrypted using the affine cipher:Alphabet: A = 0, B = 1,..., Z = 25Message:f(p) = (15p+5) mod 26

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Answered: Decrypt the message CFEJFE which was…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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An encryption function is given as f(p) = (p + y_value) mod 26 where p is the position of the input letter in English alphabets and f(p) is the position of the encrypted alphabet. Find the encrypted representation of “STOP”.
Answer number 5
Find the inverse of 17 modulo 97 9 iec t2 'N Decrypt the following message using shift cipher: f(p) = (p+ 10) mod 26 ' LO WI PBSOXN"
d out of 57 = 3 (18) + 3 g question QR + 5 ךסד Encryption of the message 'NO' by Caesar's cipher is yet ered ked out of Flag question vestion 4 -1 ot yet nswered Given that A = 3 -5 The value of 12 23 is 4 Marked out of 050 -2 7 Flag question
Let A=0, Z=25
Recall that an affine cipher, fa,b(n) = an + b( mod 26), where a, b ∈ {0, 1, 2, . . . , 25}, is said to be valid if gcd(a, 26) = 1. (a)Use the key (a, b) = (3, 0) to come up with the cipher text corresponding to the following plaintext DO WELL. (b) Now use the key (a, b) = (5, 1) to come up with the cipher text for DO WELL. (c) The key (a, b) = (5, 1) was used to generate the following cipher text. Decrypt the message. gbidxv vbfev
Determine, if possible, the affine cipher C = aP + b (mod 26) that sends plaintext "OK" to ciphertext "HI."
Apply the affine cipher formula C=(5P + 2) mod 26 to encript "LASER PRINTER". JGNSA DUNTXNA JSNAS DNUTXAN JGSAN DNUTXAN JGSAN DUNXANT
Decrypt the message EABW EFRO ATMR ASIN, which is the ciphertext produced by encrypting a plaintext message using the transposition cipher with blocks of four letters and the permutation ? of {1, 2, 3, 4} defined by ?(1) = 3, ?(2) = 1, ?(3) = 4, and ?(4) = 2.
a. Given p=23, q=7, and e=5, generate the public key (n,e) and the private key (n,d) using RSA Key generation algorithm. b. Given Bob's public key of (85, 7) and private key of (85, 55), show how Alice can encrypt m=7 to send to Bob. Show the ciphertext. c. Given Bob's public key of (85, 7) and private key of (85, 55), show how Bob can decrypt the ciphertext y=8 received from Alice. Show the plaintext. d. Using the fast exponentiation method (page 182), determine 535 mod 47

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Decrypt the message CFEJFE which was encrypted using the affine cipher: Alphabet: A = 0, B = 1,..., Z=25 Message: f(p) = (15p+5) mod 26