Declare an array of pointers named sports to store the following strings char * sports = { “football”, “basketball”, “golf”, “cricket”, “chess”, “badminton”}; Iterate over each string character by character and count the number of vowels in each string. Print the output to the console in the following form: String ’football’ contains ‘2’ vowels. They are ‘o’, ‘a’. String ’basketball’ contains ‘2’ vowels. They are ‘a’, ‘e. String ’golf’ contains ‘1’ vowel. They are ‘o’. String ’cricket’ contains ‘2’ vowels. They are ‘i’, ‘e’. String ’chess’ contains 1 vowel. It is ‘e’. String ’badminton’ contains three vowels. They are ‘a’, ‘i’, ‘o’ If a specific vocal occurs more than once in the string count it as one instance. Refer example above where football contains 2 ‘o’ vowels but it is counted as one for vowel ‘o’ Remember vowels are’: a’, ‘e’, ‘i’, ‘o’, ‘u’ To iterate over strings, you should count the number of strings as 6 by getting the size of the array of pointers Write a function called processString and pass each string to the function via pointer. The function should iterate over the string passed as parameter and count the vowels and print the values. Iterate over each string using a pointer and count the number vowels Be creative and use your logic. You are free to youw own method to solve the problem. DO NOT share information. Remember: Do not hard code any values. If I change the input array of strings by adding or removing the strings or changing the string names, your program should still work. If you read the sports data from a file and write the output to a file, you will get additional 10 bonus points.
Declare an array of pointers named sports to store the following strings
char * sports = { “football”, “basketball”, “golf”, “cricket”, “chess”, “badminton”};
Iterate over each string character by character and count the number of vowels in each string.
Print the output to the console in the following form:
String ’football’ contains ‘2’ vowels. They are ‘o’, ‘a’.
String ’basketball’ contains ‘2’ vowels. They are ‘a’, ‘e.
String ’golf’ contains ‘1’ vowel. They are ‘o’.
String ’cricket’ contains ‘2’ vowels. They are ‘i’, ‘e’.
String ’chess’ contains 1 vowel. It is ‘e’.
String ’badminton’ contains three vowels. They are ‘a’, ‘i’, ‘o’
If a specific vocal occurs more than once in the string count it as one instance. Refer example above where football contains 2 ‘o’ vowels but it is counted as one for vowel ‘o’
Remember vowels are’: a’, ‘e’, ‘i’, ‘o’, ‘u’
- To iterate over strings, you should count the number of strings as 6 by getting the size of the array of pointers
- Write a function called processString and pass each string to the function via pointer. The function should iterate over the string passed as parameter and count the vowels and print the values.
- Iterate over each string using a pointer and count the number vowels
- Be creative and use your logic. You are free to youw own method to solve the problem. DO NOT share information.
- Remember: Do not hard code any values. If I change the input array of strings by adding or removing the strings or changing the string names, your program should still work.
- If you read the sports data from a file and write the output to a file, you will get additional 10 bonus points.

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