Solve all this question... Decision D6, which has three possible choices (X, Y, or Z), must be made in year 3 of a 6-year study period in order to maximize E(PW).Using an MARR of 18% per year, the investment required in year 3, and the estimated cash flows for years 4 through 6,determine which decision should be made in year 3.D6FTTXYZHighHigh (X)Low (X)High (Y)Low (Y)High (Z)Low (Z)LowHighLowHighInvestment, Cash Flow, (Year Cash Flow, $1000Year 3(Year 4)3)34$-260,000$50$40$30Low$-52,000$-250,000The present worth of X is $The present worth of Y is $The present worth of Z is $Select decision branch Y$30$190$-30Cash Flow,$1000 (Year 5)5$50$30$40$30$170$-30Cash Flow, $1000(Year 6)6$50$20$50$30$150$-30OutcomeProbability0.720.280.450.550.70.3

PW is the present worth analysis method which can be used for evaluating various projects of…

Decision D6, which has three possible choices (X, Y, or Z), must be made in year 3 of a 6-year study period in order to maximize E Using an MARR of 18% per year, the investment required in year 3, and the estimated cash flows for years 4 through 6, determine which decision should be made in year 3. D6 X Y Z High (X) Low (X) High (Y) Low (Y) High (Z) Low (Z) High Low High Low Investment, Cash Flow, (Year Cash Flow, $1000 Year 3 3) (Year 4) 3 4 $-260,000 $50 $40 High Low $-52,000 $-250,000 The present worth of X is $ The present worth of Y is $ The present worth of Z is $ Select decision branch Y $30 $30 $190 $-30 Cash Flow, $1000 (Year 5) 5 $50 $30 $40 $30 $170 $-30 Cash Flow, $1000 (Year 6) 6 $50 $20 $50 $30 $150 $-30 Outcome Probability 0.72 0.28 0.45 0.55 0.7 0.3