decided to write an infinite sequence. Initially, he wrote 00, and then he started repeating the following process:Look at the last element written so far (the ll-th element if the sequence has length ll so far); let's denote it by xx.If xx does not occur anywhere earlier in the sequence, the next element in the sequence is 00.Otherwise, look at the previous occurrence of xx in the sequence, i.e. the kk-th element, where k<lk<l, this element is equal to xx and all elements between the k+1k+1-th and l−1l−1-th are different from xx. The next element is l−kl−k, i.e. the distance between the last two occurrences of xx.The resulting sequence is (0,0,1,0,2,0,2,2,1,…)(0,0,1,0,2,0,2,2,1,…): the second element is 00 since 00 occurs only once in the sequence (0)(0), the third element is 11 since the distance between the two occurrences of 00 in the sequence (0,0)(0,0) is 11, the fourth element is 00 since 11 occurs only once in the sequence (0,0,1)(0,0,1), and so on.Chef has given you a task to perform. Consider the NN-th element of the sequence (denoted by xx) and the first NN elements of the sequence. Find the number of occurrences of xx among these NN elements.

Answered: decided to write an infinite sequence.…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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decided to write an infinite sequence. Initially, he wrote 00, and then he started repeating the following process:

Look at the last element written so far (the ll-th element if the sequence has length ll so far); let's denote it by xx.
If xx does not occur anywhere earlier in the sequence, the next element in the sequence is 00.
Otherwise, look at the previous occurrence of xx in the sequence, i.e. the kk-th element, where k<lk<l, this element is equal to xx and all elements between the k+1k+1-th and l−1l−1-th are different from xx. The next element is l−kl−k, i.e. the distance between the last two occurrences of xx.

The resulting sequence is (0,0,1,0,2,0,2,2,1,…)(0,0,1,0,2,0,2,2,1,…): the second element is 00 since 00 occurs only once in the sequence (0)(0), the third element is 11 since the distance between the two occurrences of 00 in the sequence (0,0)(0,0) is 11, the fourth element is 00 since 11 occurs only once in the sequence (0,0,1)(0,0,1), and so on.

Chef has given you a task to perform. Consider the NN-th element of the sequence (denoted by xx) and the first NN elements of the sequence. Find the number of occurrences of xx among these NN elements.

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