Determine the critical value(s). Select the correct choice below and, if necessary, fill in the answer box to complete your choice.O A. The critical value(s) is/are.(Round to two decimal places as needed. Use a comma to separate answers as needed.)O B. The test cannot be performed.Find the z-test statistic. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.O A.Z=(Round to two decimal places as needed.)O B. The test cannot be performed.What is the result of the test?O A. Fail to reject Ho. The data do not provide sufficient evidence to support the claim.B. Reject Ho. The data provide sufficient evidence to support the claim.C. Reject Ho. The data do not provide sufficient evidence to support the claim.O D. Fail to reject Ho. The data provide sufficient evidence to support the claim.O E. The test cannot be performed. Decide whether the normal sampling distribution can be used. If it can be used, test the claim about the population proportion p at the given level of significance a using the given sample statistics.AClaim: p +0.26; a = 0.05; Sample statistics: p = 0.23, n = 100.....Can the normal sampling distribution be used?A. No, because np is less than 5.B. Yes, because both np and nq are greater than or equal to 5.C. Yes, because pq is greater than a = 0.05.D. No, because ng is less than 5.State the null and alternative hypotheses.O A. Ho: ps0.26Hạ: p>0.26В. Но: р20.26Hại p<0.26О с. Но: р3D0.26Ha: p#0.26D. The test cannot be performed.Determine the critical value(s). Select the correct choice below and, if necessary, fill in the answer box to complete your choice.O A. The critical value(s) is/are(Round to two decimal places as needed. Use a comma to separate answers as needed.)O B. The test cannot be performed.

Solution: Given information: n= 100 Sample size p^= 0.23 Sample proportion p = 0.26 Population proportion q= 1-p= 0.74α= 0.05 Level of significance The normal sampling distribution can be used because both np= 100*0.26 = 26 and nq= 100*0.74= 74 are greater than or equal to 5. Yes because both np and nq are greater than or equal to 5 Option B is Correct The null and alternative hypothesis is Ho:p=0.26Ha:p≠0.26 Option C is Correct The critical values at α=0.05 are -Zα/2=-Z0.025= -1.96 From Z table and Zα/2=Z0.025= 1.96 From Z table The critical values are -1.96, 1.96 Option A is Correct Test statistic z= p^-ppqnz =0.23-0.260.26×0.74100z =0.23-0.260.1924100z=0.23-0.260.001924z=-0.030.043863=-0.683948z= -0.68 Test statistic z = -0.68 Option A is Correct Decision Rule : Reject Ho if z > 1.96 or Reject Ho if z < -1.96 Here -0.68 > -1.96 Fail to reject Ho Conclusion: Fail to reject Ho. The data do not provide sufficient evidence to support the claim. Option A is Correct