Decane (C10H22) is the hydrocarbon combusted in diesel fuel engines, the equation is shown below. 2C10H22 + 3102 --> 20CO2 + 22H2O Select the equation that determines how many grams of decane (C10H22) are required to produce 30.0 grams of CO2. 1 mole CO2 44.01 g CO 142.276 y Cn Hn 1 mole Cho H 30.0 g CO2 2 moles C1o Hy2 1 20 noles CO2 44.01 g CO2 1 mole CO2 142.276 g Cho H2 1 mole C1aH2 1 30.0 g CO, 1 mole CO. 44.01 g CO2 142.276 g CoHn 1 nole C1o H 30.0 g CO2 1 142.276 y Cu Ha 1 nole C10 H 1 moles CgH2 44.01 g CO2 1 mole CO 1 moles CO2 30.0 g C'O2
Decane (C10H22) is the hydrocarbon combusted in diesel fuel engines, the equation is shown below. 2C10H22 + 3102 --> 20CO2 + 22H2O Select the equation that determines how many grams of decane (C10H22) are required to produce 30.0 grams of CO2. 1 mole CO2 44.01 g CO 142.276 y Cn Hn 1 mole Cho H 30.0 g CO2 2 moles C1o Hy2 1 20 noles CO2 44.01 g CO2 1 mole CO2 142.276 g Cho H2 1 mole C1aH2 1 30.0 g CO, 1 mole CO. 44.01 g CO2 142.276 g CoHn 1 nole C1o H 30.0 g CO2 1 142.276 y Cu Ha 1 nole C10 H 1 moles CgH2 44.01 g CO2 1 mole CO 1 moles CO2 30.0 g C'O2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:Decane (C10H22) is the hydrocarbon combusted in diesel fuel engines, the equation is
shown below.
2C10H22 + 3102 --> 20CO2 + 22H20
Select the equation that determines how many grams of decane (C10H22) are required to
produce 30.0 grams of CO2.
1 mole CO
44.01 g CO,
142.276 y Cn H2
1 mole Cho H
30.0 g CO2
2 moles C1o H2
1
20 snoles CO2
44.01 g CO2
1 mole CO2
142.276 g Co H2
1 mole C1aHz
30.0 g CO2
142.276 g Co H3
1 niole C1o H
30.0 g CO2
1 mole CO.
1
44.01 g CO,
44.01 g CO2
1 mole CO
1 moles CoHz2
1 moles CO,
142.276 y Cu H23
1 mole C10H2
30.0 g CO2
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