Decane (C10H22) is the hydrocarbon combusted in diesel fuel engines, the equation is shown below. 2C10H22 + 3102 --> 20CO2 + 22H2O Select the equation that determines how many grams of decane (C10H22) are required to produce 30.0 grams of CO2. 1 mole CO2 44.01 g CO 142.276 y Cn Hn 1 mole Cho H 30.0 g CO2 2 moles C1o Hy2 1 20 noles CO2 44.01 g CO2 1 mole CO2 142.276 g Cho H2 1 mole C1aH2 1 30.0 g CO, 1 mole CO. 44.01 g CO2 142.276 g CoHn 1 nole C1o H 30.0 g CO2 1 142.276 y Cu Ha 1 nole C10 H 1 moles CgH2 44.01 g CO2 1 mole CO 1 moles CO2 30.0 g C'O2

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
100%
Decane (C10H22) is the hydrocarbon combusted in diesel fuel engines, the equation is
shown below.
2C10H22 + 3102 --> 20CO2 + 22H20
Select the equation that determines how many grams of decane (C10H22) are required to
produce 30.0 grams of CO2.
1 mole CO
44.01 g CO,
142.276 y Cn H2
1 mole Cho H
30.0 g CO2
2 moles C1o H2
1
20 snoles CO2
44.01 g CO2
1 mole CO2
142.276 g Co H2
1 mole C1aHz
30.0 g CO2
142.276 g Co H3
1 niole C1o H
30.0 g CO2
1 mole CO.
1
44.01 g CO,
44.01 g CO2
1 mole CO
1 moles CoHz2
1 moles CO,
142.276 y Cu H23
1 mole C10H2
30.0 g CO2
Transcribed Image Text:Decane (C10H22) is the hydrocarbon combusted in diesel fuel engines, the equation is shown below. 2C10H22 + 3102 --> 20CO2 + 22H20 Select the equation that determines how many grams of decane (C10H22) are required to produce 30.0 grams of CO2. 1 mole CO 44.01 g CO, 142.276 y Cn H2 1 mole Cho H 30.0 g CO2 2 moles C1o H2 1 20 snoles CO2 44.01 g CO2 1 mole CO2 142.276 g Co H2 1 mole C1aHz 30.0 g CO2 142.276 g Co H3 1 niole C1o H 30.0 g CO2 1 mole CO. 1 44.01 g CO, 44.01 g CO2 1 mole CO 1 moles CoHz2 1 moles CO, 142.276 y Cu H23 1 mole C10H2 30.0 g CO2
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Stoichiometry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY