Decane (C10H22) is the hydrocarbon combusted in diesel fuel engines, the equation is shown below. 2C10H22 + 3102 --> 20CO2 + 22H2O Select the equation that determines how many grams of decane (C10H22) are required to produce 30.0 grams of CO2. 1 mole CO2 44.01 g CO 142.276 y Cn Hn 1 mole Cho H 30.0 g CO2 2 moles C1o Hy2 1 20 noles CO2 44.01 g CO2 1 mole CO2 142.276 g Cho H2 1 mole C1aH2 1 30.0 g CO, 1 mole CO. 44.01 g CO2 142.276 g CoHn 1 nole C1o H 30.0 g CO2 1 142.276 y Cu Ha 1 nole C10 H 1 moles CgH2 44.01 g CO2 1 mole CO 1 moles CO2 30.0 g C'O2
Decane (C10H22) is the hydrocarbon combusted in diesel fuel engines, the equation is shown below. 2C10H22 + 3102 --> 20CO2 + 22H2O Select the equation that determines how many grams of decane (C10H22) are required to produce 30.0 grams of CO2. 1 mole CO2 44.01 g CO 142.276 y Cn Hn 1 mole Cho H 30.0 g CO2 2 moles C1o Hy2 1 20 noles CO2 44.01 g CO2 1 mole CO2 142.276 g Cho H2 1 mole C1aH2 1 30.0 g CO, 1 mole CO. 44.01 g CO2 142.276 g CoHn 1 nole C1o H 30.0 g CO2 1 142.276 y Cu Ha 1 nole C10 H 1 moles CgH2 44.01 g CO2 1 mole CO 1 moles CO2 30.0 g C'O2
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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