Dean thinks that AB + A'B' simplifies to 1 by the Inverse law. A. Show that Dean is wrong by fleshing out a truth table to find all rows in which AB + A'B' evaluates to 0, not 1. Circle these rows. B. By part (a), A'B' is clearly not the inverse of AB. Using DeMorgan’s law, express the inverse of AB as a Boolean expression bexp5b that is a sum of literals. C.  Extend the truth table from part (a) to add columns for bexp5b and AB + bexp5b. All entries in the column for AB + bexp5b should have the value 1, showing that bexp5b is indeed the inverse of AB.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Dean thinks that AB + A'B' simplifies to 1 by the Inverse law.

A. Show that Dean is wrong by fleshing out a truth table to find all rows in which AB + A'B' evaluates to 0, not 1. Circle these rows.

B. By part (a), A'B' is clearly not the inverse of AB. Using DeMorgan’s law, express the inverse of AB as a Boolean expression bexp5b that is a sum of literals.

C.  Extend the truth table from part (a) to add columns for bexp5b and AB + bexp5b. All entries in the column for AB + bexp5b should have the value 1, showing that bexp5b is indeed the inverse of AB.

Expert Solution
Step 1: Introduction

Given that:

AB+A'B'=1 by the inverse law:

To show that:

A) Dean is wrong by using truth table.

B) express the inverse of AB as a Boolean expression bexp5b that is a sum of literals.

C) showing that bexp5b is indeed the inverse of AB.

Concept:

To demonstrate that Dean is wrong and that  does not simplify to 1,

Let's create a truth table that evaluates the expression for all possible combinations of inputs  and .

We will circle the rows where the expression evaluates to 0.

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