Dean thinks that AB + A'B' simplifies to 1 by the Inverse law. A. Show that Dean is wrong by fleshing out a truth table to find all rows in which AB + A'B' evaluates to 0, not 1. Circle these rows. B. By part (a), A'B' is clearly not the inverse of AB. Using DeMorgan’s law, express the inverse of AB as a Boolean expression bexp5b that is a sum of literals. C. Extend the truth table from part (a) to add columns for bexp5b and AB + bexp5b. All entries in the column for AB + bexp5b should have the value 1, showing that bexp5b is indeed the inverse of AB.
Dean thinks that AB + A'B' simplifies to 1 by the Inverse law.
A. Show that Dean is wrong by fleshing out a truth table to find all rows in which AB + A'B' evaluates to 0, not 1. Circle these rows.
B. By part (a), A'B' is clearly not the inverse of AB. Using DeMorgan’s law, express the inverse of AB as a Boolean expression bexp5b that is a sum of literals.
C. Extend the truth table from part (a) to add columns for bexp5b and AB + bexp5b. All entries in the column for AB + bexp5b should have the value 1, showing that bexp5b is indeed the inverse of AB.
Given that:
AB+A'B'=1 by the inverse law:
To show that:
A) Dean is wrong by using truth table.
B) express the inverse of AB as a Boolean expression bexp5b that is a sum of literals.
C) showing that bexp5b is indeed the inverse of AB.
Concept:
To demonstrate that Dean is wrong and that does not simplify to 1,
Let's create a truth table that evaluates the expression for all possible combinations of inputs and .
We will circle the rows where the expression evaluates to 0.
Step by step
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