**Description and Task:****DBU (short for 1,8-Diazabicyclo[5.4.0]undec-7-ene)** is what is called a non-nucleophilic base because it will preferentially react via an E2 reaction over an SN2 reaction. Write the products of the following E2 reaction:**Chemical Equation:**- **DBU** (structural formula: a bicyclic compound with two nitrogen atoms)- **CH3CH2Br** (ethyl bromide)**Reaction:**- Reactants: DBU + CH3CH2Br- Products: Results from an E2 elimination reaction leading to the formation of ethylene (CH2=CH2).**Task:**a) Write the mechanism.**Explanation:**- **Diagram:** The diagram shows a bicyclic compound labeled as DBU on the left, reacting with ethyl bromide (CH3CH2Br) to undergo an E2 reaction.- **Mechanism:** - In an E2 reaction, the base (DBU) abstracts a proton from the β-carbon adjacent to the leaving group (Br). - This results in the simultaneous formation of a double bond and the expulsion of the leaving group (Br-), leading to the formation of ethylene (CH2=CH2).

Number of functional group is associated with organic compounds which impart specific chemical and…

DBU (short for 1,8-Diazabicyclo[5.4.0]undec-7-ene) is what is called a non-nucleophilic base because it will preferentially react via an E2 reaction over an SN2 reaction. Write the products of the following E2 reaction: DBU E2 CH;CH,Br a) Write the mechanism.

DBU (short for 1,8-Diazabicyclo[5.4.0]undec-7-ene) is what is called a non-nucleophilic base because it will preferentially react via an E2 reaction over an SN2 reaction. Write the products of the following E2 reaction: DBU E2 CH;CH,Br a) Write the mechanism.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Aromatic Compounds

Aromatic organic compound or aromatic system is an important class of hydrocarbons under the branch of organic chemistry. Aromatic compounds are also called arenas. The definition of aromatic organic compounds can be stated as a class of organic compounds with a planar cyclic ring of atoms bonded through alternated single and double bonds. Due to these alternating bonds, a peculiar feature termed as ‘resonance’, that is, delocalization of pi electrons or the electrons is shared within the atoms of the ring which are present in the aromatic compounds. The word ‘aromatic’ includes a Greek word ‘aroma’ which means smell, indicating that they were named as such due to the sweet odor they produce. Many well-known flavors such as vanilla, cinnamon, and few scents from flowers are extracted from aromatic compounds. Benzene with chemical formula C6H6 is a very common aromatic compound that contains six atoms of carbon held in the cyclic ring of alternate double bonds. It is also to be noted that not all aromatic compounds contain benzene ring. This can be explained by Huckel’s rule.

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**Description and Task:**

**DBU (short for 1,8-Diazabicyclo[5.4.0]undec-7-ene)** is what is called a non-nucleophilic base because it will preferentially react via an E2 reaction over an S<sub>N</sub>2 reaction. Write the products of the following E2 reaction:

**Chemical Equation:**

- **DBU** (structural formula: a bicyclic compound with two nitrogen atoms)

- **CH<sub>3</sub>CH<sub>2</sub>Br** (ethyl bromide)

**Reaction:**

- Reactants: DBU + CH<sub>3</sub>CH<sub>2</sub>Br
- Products: Results from an E2 elimination reaction leading to the formation of ethylene (CH<sub>2</sub>=CH<sub>2</sub>).

**Task:**

a) Write the mechanism.

**Explanation:**

- **Diagram:** The diagram shows a bicyclic compound labeled as DBU on the left, reacting with ethyl bromide (CH<sub>3</sub>CH<sub>2</sub>Br) to undergo an E2 reaction.

- **Mechanism:**
- In an E2 reaction, the base (DBU) abstracts a proton from the β-carbon adjacent to the leaving group (Br).
- This results in the simultaneous formation of a double bond and the expulsion of the leaving group (Br<sup>-</sup>), leading to the formation of ethylene (CH<sub>2</sub>=CH<sub>2</sub>).

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