Dayer diagnostics claims that their latest imaging equipment can identify signs ofdementia with Sensitivity dementia = 0.60 ; and low-grade tumour withSpecificitytumour = 0.60 . Assume that the diagnostic outcomes of bothdiseases are independent. Which of the following is correct about the tool?If the claims are true, then Sensitivitytumour = 0.60.If the claims are true, the probability that a dementia patient is tested negative fordementia is 0.60.Correct AnswerThere is insufficient information to calculate the negative predictive value for tumourdiagnosis with their claim.

Solution Dayer diagnostics claims that their latest imaging equipment can identify signs of dementia…

Answered: Dayer diagnostics claims that their…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Pregnant women are screened for a birth defect called Down syndrome. Down syndrome babies are mentally and physically challenged. Some mothers choose to abort the fetus when they are certain that their baby will be born with the syndrome. The most common screening is maternal serum screening, a blood test that looks for markers in the blood to indicate whether the birth defect may occur. The false-positive and false-negative rates vary according to the age of the mother. Mother’s Age False-Positive Rate False-Negative RateUnder 30 0.040 0.37630-34 0.082 0.29035-37 0.178 0.269Over 38 0.343 0.029 The probability that a baby has Down syndrome is primarily a function of the mother’s age. The probabilities are listed here. Age Probability of Down Syndrome25 1/130030 1/90035 1/35040 1/10045 1/2549 1/12 For each of the age 25, 30, 35, 40, 45 and 49, determine the probability of Down syndrome if the maternity serum screening produces a…
A random sample of 40 computer chips is drawn from population and the weight of each recorded. A previous study showed that the population mean weight was 0.8 ounces with a standard deviation of 0.1 ounces. What is the probability that the sample has a mean weight between 0.75 and 0.90 ounces?
If arrivals occur at a mean rate of 2.6 events per minute the exponential probability of waiting more than 1.5 minutes for the next arrival is is a .0202 or .0122 or .0535 or .2564
Cody took his first physics exam and scored an 80. The population mean for this exam is 70, and the standard deviation is 5. What is the probability of selecting a person with a score greater than Cody’s?
The producer of a weight-loss pill advertises that people who use the pill lose, after one week, an average (mean) of 1.8 pounds with a standard deviation of 0.95 pounds. In a recent study, a group of 45 people who used this pill were interviewed. The study revealed that these people lost a mean of 1.92 pounds after one week. If the producer's claim is correct, what is the probability that the mean weight loss after one week on this pill for a random sample of 45 individuals will be 1.92 pounds or less? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
A dean in the business school claims that GMAT scores of applicants to the school's MBA program have increased during the past 5 years. Five years ago, the mean and standard deviation of GMAT scores of MBA applicants were 550 and 60, respectively. 30 applications for this year's program were randomly selected and the GMAT scores recorded. If we assume that the distribution of GMAT scores of this year's applicants is the same as that of 5 years ago, find the probability of erroneously concluding that there is not enough evidence to supports the claim when, in fact, the true mean GMAT score is 590. Assume αα is 0.02.
An appliance dealer's website features the mean life expectancy values for major household appliances. A freezer's mean life expectancy is 16 years with a standard deviation of 2 years. Using the Empirical Rule, what is the probability that your freezer will function less than 10 years
For a hypothesis test of a single population mean with unknown population standard deviation (σσ), we can use either Geogebra or Minitab. In Geogebra: use the “Statistics” tab in the Probability Calculator. Click the drop-down menu near the top (default is “Z Test of a Mean”) and choose “T Test of a Mean.” In Minitab: Select Stat > Basic Statistics > 1 sample t. Select Summarized Data from the drop-down menu. Check mark “Perform Hypothesis Test” and enter the hypothesized value. Click Options and select the appropriate alternate hypothesis. For both: Enter the sample mean, sample standard deviation, and sample size. We’ll use a sample with x¯=73.2, s=14.16, n=16. For a hypothesis test of H0:μ=70 versus HA:μ >70 The given sample has a test statistic of The P-value for the test is For a hypothesis test of H0:μ=75 versus HA:μ<75H0:μ=75 versus HA:μ<75: The given sample has a test statistic of The P-value for the test is For a hypothesis test of H0:μ=75 versus…
The NJ Department of Health has reported the average life span of NJ residents is 81 years. If the standard deviation is σ = 4 years, what is the probability of a person living to at least 92 years of age?
For a hypothesis test of a single population mean with unknown population standard deviation (σ�), we can use either Geogebra or Minitab. In Geogebra: use the “Statistics” tab in the Probability Calculator. Click the drop-down menu near the top (default is “Z Test of a Mean”) and choose “T Test of a Mean.” In Minitab: Select Stat > Basic Statistics > 1 sample t. Select Summarized Data from the drop-down menu. Check mark “Perform Hypothesis Test” and enter the hypothesized value. Click Options and select the appropriate alternate hypothesis. For both: Enter the sample mean, sample standard deviation, and sample size. We’ll use a sample with x¯=73.2�¯=73.2, s=14.16�=14.16, n=16�=16. For a hypothesis test of H0:μ=70 versus HA:μ>70�0:�=70 versus ��:�>70: The given sample has a test statistic of equation editor Equation Editor . The P-value for the test is equation editor Equation Editor . For a hypothesis test of H0:μ=75 versus HA:μ<75�0:�=75 versus…
Suppose a life insurance company sells a $170,000 1-year term life insurance policy to a 20-year-old female for $300. According to the National Vital Statistics Report, 58(21), the probability that the female survives the year is 0.999544. The expected value of this policy to the insurance company is$222.48. What is the standard deviation of the value of the life insurance policy? Why is the value so high? Part 1 The standard deviation of the value of the life insurance is $
Consider two data sets from sampled populations, one with a high standard deviation and one with a low standard deviation. All else being equal, which dataset would have a lower probability of a Type One error?

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