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dªy Using the reduction of order method, find the general solution of the differential equation dx4 A. None of these. B. 13 3 13 4 1 ·x + 5x y=x+x²_ - - 150 120 125 C. 13 3 13 4 5x - - y = C₁+C₁₂x+c ₂₁x². 390 312 125 where C1, C2, C3, C4 are arbitrary constants. D. 5x --- y = C₁ + ₂x+c₁₂₁²_ 13 3 13 4 120 ·x + e 150 125 where C1, C2, C3, C4 are arbitrary constants. OE 13 13 5x y = C₁ + C₂x+c ₂₁x² +- -x +- e 150 120 125 ·x + CA e d³y dx3 5. = 13x

dªy Using the reduction of order method, find the general solution of the differential equation dx4 A. None of these. B. 13 3 13 4 1 ·x + 5x y=x+x²_ - - 150 120 125 C. 13 3 13 4 5x - - y = C₁+C₁₂x+c ₂₁x². 390 312 125 where C1, C2, C3, C4 are arbitrary constants. D. 5x --- y = C₁ + ₂x+c₁₂₁²_ 13 3 13 4 120 ·x + e 150 125 where C1, C2, C3, C4 are arbitrary constants. OE 13 13 5x y = C₁ + C₂x+c ₂₁x² +- -x +- e 150 120 125 ·x + CA e d³y dx3 5. = 13x

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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day Using the reduction of order method, find the general solution of the differential equation dx4 A. None of these. B. 13 3 13 4 1 5x ·x + ^y=x+x² - e 150 120 125 13 C4 5x y = C²₁₂ + C²₂₁²x + C ₁₂₁x₁² - 390 312 125 where C1, C2, C3, C4 are arbitrary constants. D. 13 3 13 C45x 4 X x² + e y = C₁₂ + C₁₂³x² + C²₂₁²²²_ 150 120 125 where C1, C2, C3, C4 are arbitrary constants. O E 13 -x²³² + 13 C4 4 5x y = C₁₂ + C²₂₁x² + C²₁₂₁x² +. 150 120 125 where C1, C2, C3, C4 are arbitrary constants. OC. - 13 3 - 4 x + e e d3 5. dx³ = 13x
Transcribed Image Text:day Using the reduction of order method, find the general solution of the differential equation dx4 A. None of these. B. 13 3 13 4 1 5x ·x + ^y=x+x² - e 150 120 125 13 C4 5x y = C²₁₂ + C²₂₁²x + C ₁₂₁x₁² - 390 312 125 where C1, C2, C3, C4 are arbitrary constants. D. 13 3 13 C45x 4 X x² + e y = C₁₂ + C₁₂³x² + C²₂₁²²²_ 150 120 125 where C1, C2, C3, C4 are arbitrary constants. O E 13 -x²³² + 13 C4 4 5x y = C₁₂ + C²₂₁x² + C²₁₂₁x² +. 150 120 125 where C1, C2, C3, C4 are arbitrary constants. OC. - 13 3 - 4 x + e e d3 5. dx³ = 13x
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