Data Sheet # of Neutrons in 20F 11 Channel A: Trial #1 -.04524 slope Channel A: Trial #1 6.2984 y-intercept Channel A: Trial #1 In plot Channel A: Trial #2 raw plot Channel A: Trial #2 -.02477 slope Channel A: Trial #2 5.7071 y-intercept Channel A: Trial #3 In plot 迪 Channel A: Trial #3 slope -.02252 Channel A: Trial #3 5.5112 y-intercept Channel A: Trial #4 迪 SECTION 16 The intensity of emitted gamma rays at a given energy is known to be directly proportional to the abundance of unstable isotopes that decay with that emission. Thus, the intensity of gamma rays emitted at 1.634 MeV is a measure of the abundance of 20F nuclei. The plot of Ln (intensity) vs time gives a linear response with slope = -k. Calculate the half-life, t₁/2, using equation (7), for 20F from each of the six replicate channel A runs and enter your results below. Be sure to use the correct number of sig figs in your responses. Remember, the slope values you measured can be displayed by clicking on the Data Sheet tab. Attempt: 1/3 You are outside of the expected range. Try again. 20F 1/2 value (run #1) -15.318 Attempt: 1/3 You are outside of the expected range. Try again. 20F 1/2 value (run #2) -27.977 S
Data Sheet # of Neutrons in 20F 11 Channel A: Trial #1 -.04524 slope Channel A: Trial #1 6.2984 y-intercept Channel A: Trial #1 In plot Channel A: Trial #2 raw plot Channel A: Trial #2 -.02477 slope Channel A: Trial #2 5.7071 y-intercept Channel A: Trial #3 In plot 迪 Channel A: Trial #3 slope -.02252 Channel A: Trial #3 5.5112 y-intercept Channel A: Trial #4 迪 SECTION 16 The intensity of emitted gamma rays at a given energy is known to be directly proportional to the abundance of unstable isotopes that decay with that emission. Thus, the intensity of gamma rays emitted at 1.634 MeV is a measure of the abundance of 20F nuclei. The plot of Ln (intensity) vs time gives a linear response with slope = -k. Calculate the half-life, t₁/2, using equation (7), for 20F from each of the six replicate channel A runs and enter your results below. Be sure to use the correct number of sig figs in your responses. Remember, the slope values you measured can be displayed by clicking on the Data Sheet tab. Attempt: 1/3 You are outside of the expected range. Try again. 20F 1/2 value (run #1) -15.318 Attempt: 1/3 You are outside of the expected range. Try again. 20F 1/2 value (run #2) -27.977 S
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
the formula they are refering to fot 1/2 time is .693/k. I thought K was slope so I plugged that in and do not know why I got these wrong.
Transcribed Image Text:Data Sheet
# of Neutrons in 20F
11
Channel A: Trial #1
-.04524
slope
Channel A: Trial #1
6.2984
y-intercept
Channel A: Trial #1
In plot
Channel A: Trial #2
raw plot
Channel A: Trial #2
-.02477
slope
Channel A: Trial #2
5.7071
y-intercept
Channel A: Trial #3
In plot
迪
Channel A: Trial #3
slope
-.02252
Channel A: Trial #3
5.5112
y-intercept
Channel A: Trial #4
迪
SECTION 16
The intensity of emitted gamma rays at a given
energy is known to be directly proportional to the
abundance of unstable isotopes that decay with that
emission. Thus, the intensity of gamma rays emitted
at 1.634 MeV is a measure of the abundance of 20F
nuclei. The plot of Ln (intensity) vs time gives a linear
response with slope = -k.
Calculate the half-life, t₁/2, using equation (7), for 20F
from each of the six replicate channel A runs and
enter your results below. Be sure to use the correct
number of sig figs in your responses. Remember, the
slope values you measured can be displayed by
clicking on the Data Sheet tab.
Attempt: 1/3
You are outside of the expected range. Try again.
20F 1/2 value (run #1)
-15.318
Attempt: 1/3
You are outside of the expected range. Try again.
20F 1/2 value (run #2)
-27.977
S
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