Data from Various Sources (VP in mm Hg; T in °C) Compound A B C Temperature Range, "C Benzene 6.90565 1211.033 220.79 Benzene 6.87987 1196.76 219.161 8-80 Toluene 6.95087 1342.31 219.187 -27-111 n-Butane 6.809 935.86 238.73 n-Pentane 6.853 1064.8 233.01 n-Hexane 6.876 1171.17 224.41 Acetone 7.63132 1566.69 273.419 57-205 Methanol 8.08097 1582.271 239.726 15-84 Ethanol 8.11220 1592.864 226.184 20-93 Ethanol 8.32109 1718.10 237.52 -2-100 water 8.01767 1715.70 234.268 100-265 Methanol 5.20409 1581.341 -33.50 288.1-356.83 Ethanol 5.24677 1598.673 -46.424 292.77-366.63 1-Propanol 5.31384 1690.864 -51.804 292.4-370.5 Isopropanol 4.8610 1357.427 -75.814 329.92-362.41 1-Butanol 4.54607 1351.555 -93.34 295.8-391.0 2-Butanol 4.32943 1158.672 -104.683 354.54-380.30 1-Octanol 4.80915 1753.525 -99.0 328.02-387.0 Water 4.6543 1435.264 -64.848 255.9-373
Antoine constants for vapor pressure for n-pentane and n-hexane are listed in Table 2-3.
a. Predict the vapor pressure at 0.0°C for pure n-pentane.
b. Predict the boiling point of pure n-pentane at 3.0 atm pressure.
c. Predict the boiling pressure if pure n-pentane is boiling at 0.0°C.
d. At a pressure of 500.0 mm Hg and temperature of 30.0°C, predict the K values for n-pentane and n-hexane using Raoult’s law.
e. If T = 30.0°C and p = 500.0 mm Hg, determine the mole fractions in the liquid and vapor phases of an equilibrium mixture of n-pentane and n-hexane.
f. 1.0 moles of a mixture that is 75.0 mol% n-pentane and 25.0 mol% n-hexane is placed in a closed chamber. The pressure is adjusted to 500.0 mm Hg, and the temperature to 30.0°C. The vapor and liquid mole fractions were found in part e. How many moles of liquid and moles of vapor are there at equilibrium?
g. If 1.0 mol/min of a mixture that is 75.0 mol% n-pentane and 25.0 mol% n-hexane is fed continuously to an equilibrium flash chamber operating at 30.0°C and 500.0 mm Hg, find the flow rates of the liquid and vapor products.
Step by step
Solved in 2 steps with 6 images
