Danielle launches a ball off of a platform of height h with velocity vo at an angle above the horizontal. A wall with a ball-sized hole a height H above the floor, with H > h, is a horizontal distance L = 17.5 m away from Danielle. The difference in height between H and h is one-fifth of L, and the square of the magnitude of the velocity, , is five-fourths of the product gL.
Danielle launches a ball off of a platform of height h with velocity vo at an angle above the horizontal. A wall with a ball-sized hole a height H above the floor, with H > h, is a horizontal distance L = 17.5 m away from Danielle. The difference in height between H and h is one-fifth of L, and the square of the magnitude of the velocity, , is five-fourths of the product gL.
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Determine the two values of theta that ensure the ball passes through the hole. Submit the large angle as theta 1 and the smaller angle as theta 2
Transcribed Image Text:Macmillan Learning
Danielle launches a ball off of a platform of height h with
velocity vo at an angle above the horizontal. A wall with a
ball-sized hole a height H above the floor, with H > h, is a
horizontal distance L =
17.5 m away from Danielle. The
difference in height between H and h is one-fifth of L, and
the square of the magnitude of the velocity, , is five-fourths
of the product gL.
0₁ =
H - h =
=
v²
1
L
Determine the two values of 0 that ensure the ball passes
through the hole. Submit the larger angle as 0₁ and the
smaller angle as 02.
5
78L
O
h
0₂:
=
0
9
L
H
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