Daniel claimed that the equation x2 +36 = 0 can be solved by using its factored form of (x + 6i)(x – 6i) = 0. He stated that there are two solutions zeros for this %3D function: -6i and 6i. Choice Description Daniel is incorrect. The factored form of x2 +36 = 0 is (x + 6i)2 = 0, A and there is only one zero of 6i. Daniel is incorrect. The factored form of x? +36 = 0 is (x + 6i)2 = 0, %3D and there is only one zero of -6i. Daniel is partially correct. The factored form of a2 +36 = 0 is (x+6i)(x- 6i) = 0, but the zeros are 6 and -6. %3D C %3D Daniel is correct. The factored form of x2 + 36 = 0 is (x + 6i)(x – 6i) = 0, and the zeros are 6i and –6i. %3D O Choice A O Choice B O Choice C O Choice D B.

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