A manufacturer of aspirin claims that the proportion of headache sufferers who get relief with just two aspirins is 63.4%. What is the probability that in a random sample of 490 headache sufferers, nomore than 289 obtain relief?Remember to use the continuity correction and calculate z-scores to at least 3 decimal places. Give probabilities to 4 decimal places.Probability =%3Dpreview answers

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A courier service makes an average of 500 deliveries a week, plus / minus 50. The manager wants to know the probability that, on average, between 490 and 510 deliveries will be made during the next 30 weeks. Write your answer to 5 decimal places.
According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 inches and a standard deviation of 2.5 inches. Suppose one Asian adult male is randomly chosen. Let X = height of the individual. Find the probability that the person is between 64 and 69 inches. The middle 40% of heights fall between what two values?Write the probability statement. State the two values. (Round your answers to one decimal place.) x1,x2 ch6#9
Suppose that 72% of Veterinary School graduates who take the licensure exam for their state pass the exam. Find the approximate probability that at least 75% of 150 randomly sampled people taking the Veterinarian licensure exam will pass the exam. Round your answer to four decimal places.
One half of the people in the United States own individual stocks. In a random sample of 12 people, what is the probability that the number owning individual stocks is less than 4. Round to 3 decimal places.
Corporation X manufactures light bulbs. The CEO claims that an average the light bulb lasts 300 days. A researcher randomly selects 15 bulbs for testing. The sampled bulbs last an average of 290 days, SD of 50 days. If the CEO's claim were true, what is the probability that 15 randomly selected bulbs would have an average life of no more than 290 days? Use 3 decimal places. Do not put a % sign. Answer:
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Find the indicated probability and interpret the result. From 1975 through 2020, the mean annual gain of the Dow Jones Industrial Average was 653. A random sample of 34 years is selected from this population. What is the probability that the mean gain for the sample was between 400 and 800? Assume o = 1540. The probability is (Round to four decimal places as needed.) Interpret the result. Select the correct choice and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. About OB. About OC. About OD. About % of samples of 46 years will have an annual mean gain between 400 and 800. % of samples of 34 years will have an annual mean gain between 653 and 800. % of samples of 34 years will have an annual mean gain between 400 and 800. % of sampl of 34 years will have an annual mean gain between 400 and 653.
In a recent survey, 76.38% has said that they use any social media. If 20 adults are selected at random, find the probability that exactly 11 say that they use social media. Round your answer to 3 decimal places.
The table summarizes results from 975 pedestrian deaths that were caused by automobile accidents. DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 45 74 No 285 571 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was not intoxicated.Report the answer as a percent rounded to one decimal place accuracy.
The table summarizes results from 979 pedestrian deaths that were caused by automobile accidents. DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 59 74 No 248 598 If two different pedestrian deaths are randomly selected, find the probability that they both involved pedestrians that were not intoxicated.Report the answer as a percent with two decimal places accuracy. (You need not enter the "%" symbol).Probability = %
The mean percent of childhood asthma prevalence in 43 cities is 2.38%. A random sample of 30 of these cities is selected. What is the probability that the mean childhood asthma prevalence for the sample is greater than 2.8%? Interpret this probability. Assume that o = 1.25%. The probability is (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. About % of samples of 43 cities will have a mean childhood asthma prevalence greater than 2.8%. O B. About % of samples of 30 cities will have a mean childhood asthma prevalence greater than 2.38%. O C. About % of samples of 30 cities will have a mean childhood asthma prevalence greater than 2.8%. Click to select your answer(s). P Type here to search 99+ a (? 1:42 PM 4/11/2021 ho insen 144 ese & t backspace %23 3. %24 4 6. 8 2. Y W tab H. J. K pase 5 R
The table summarizes results from 975 pedestrian deaths that were caused by automobile accidents. DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 49 73 No 221 632 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated.Report the answer as a percent rounded to one decimal place accuracy. prob = %

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