Δ60-ΔΗ-TΔS, and AG°=-nFE°cell, show that: AS° = AH° AT. (G) A + nFE°cell) %3D

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Chapter1: Chemical Foundations
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Find Delta H° for the overall reaction.
AG°=AH°-TAS°, and
AG°=-nFE°cell,
show that:
AS° = AH°
+nFE°cell)
Transcribed Image Text:AG°=AH°-TAS°, and AG°=-nFE°cell, show that: AS° = AH° +nFE°cell)
Consider the following two half redox reactions
Reduction: 2H* (aq) + 2e H2 (g) , E°= 0.00 V
Oxidation: X, (g) →2X (g) + 2e
E° = ? V
The overall reaction is
2H* (aq) +X2 (g) →H2 (g) + 2X (aq)
The Following Data were obtained for the overall reaction at different temperature.
AS°(J/mol.K)
T(K)
629
890
700
715
790
500
820
298
1200
45
2690
10
Transcribed Image Text:Consider the following two half redox reactions Reduction: 2H* (aq) + 2e H2 (g) , E°= 0.00 V Oxidation: X, (g) →2X (g) + 2e E° = ? V The overall reaction is 2H* (aq) +X2 (g) →H2 (g) + 2X (aq) The Following Data were obtained for the overall reaction at different temperature. AS°(J/mol.K) T(K) 629 890 700 715 790 500 820 298 1200 45 2690 10
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