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d. Write the equation for the power as a function of time. e. You measure the rms current (with a multimeter) to be 3 A. What is the peak voltage across the resistor? [8.25 V] f. Write the equation for the voltage as a function of time. g. Write the equation for the current as a function of time.

d. Write the equation for the power as a function of time. e. You measure the rms current (with a multimeter) to be 3 A. What is the peak voltage across the resistor? [8.25 V] f. Write the equation for the voltage as a function of time. g. Write the equation for the current as a function of time.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Help with parts d to the end please

19. Below is a graph of the power used by a resistor 40 35 30 25 20 15 10 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 time (seconds) a. What is the peak power used by the resistor? b. What is the average power used by the resistor? c. What is the period of the power? (hint – remember this is a sin squared function. The negative part of the normal sine function is flipped positive. So you have to go over two bumps to get back to the start of the wave.) d. Write the equation for the power as a function of time. e. You measure the rms current (with a multimeter) to be 3 A. What is the peak voltage across the resistor? [8.25 V] f. Write the equation for the voltage as a function of time. g. Write the equation for the current as a function of time. power (watts)
Transcribed Image Text:19. Below is a graph of the power used by a resistor 40 35 30 25 20 15 10 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 time (seconds) a. What is the peak power used by the resistor? b. What is the average power used by the resistor? c. What is the period of the power? (hint – remember this is a sin squared function. The negative part of the normal sine function is flipped positive. So you have to go over two bumps to get back to the start of the wave.) d. Write the equation for the power as a function of time. e. You measure the rms current (with a multimeter) to be 3 A. What is the peak voltage across the resistor? [8.25 V] f. Write the equation for the voltage as a function of time. g. Write the equation for the current as a function of time. power (watts)
Expert Solution
Step 1

The given graph is power waveform. 

What is power equation, voltage equation, current equation. 

What is peak voltage if rms current Irms = 3A.

 

 

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