This is my professor's solution to 33d and I just need an explanation for 33d.Why didn't we find all values in the binomial probability table for Y less than or equal 7 and add them up like we did in 33c? Why did we find P(X>7)? 5.33 Cyberbullying. A survey of 4972 U.S. students aged 12 to 17 years revealsthat 25% have received mean or hurtful comments online in the past 30 days.¹⁹You take a random sample of 15 undergraduates and ask them whether theyhave received mean or hurtful comments online in the past 30 days. If the rate atyour university matches this 25% rate:a. What is the distribution of the number of undergraduates who say thatthey have received hurtful comments online in the past 30 days?b. What is the distribution of the number of undergraduates who say thatthey have not received hurtful comments online in the past 30 days?c. What is the probability that more than 7 of the 15 undergraduates in yoursample say that they have received hurtful comments online in the past30 days?d. What is the probability that no more than 7 of the 15 students in yoursample say that they have not received hurtful comments online in thepast 30 days? (5.33p.320ck: 15 (1) (4972) = 497.2 ⇒ binomial model is good,a) X=# who have received mean comments, ~ (Bi(1525)b) Y = # who haven't~ Bi (15,75)15) = ₂0393 +₁0131+.0034 +0007 +.0001 ==60566P(X>7) = P(8, 9, 10,1d) P(Y ≤ 7) = P(X) 17) =60566

d. The given sample size is 15 and probability of success 0.25.

Answered: d. What is the probability that no more…

d. What is the probability that no more than 7 of the 15 students in your sample say that they have not received hurtful comments online in the past 30 days?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

This is my professor's solution to 33d and I just need an explanation for 33d.

Why didn't we find all values in the binomial probability table for Y less than or equal 7 and add them up like we did in 33c? Why did we find P(X>7)?

5.33 Cyberbullying. A survey of 4972 U.S. students aged 12 to 17 years reveals
that 25% have received mean or hurtful comments online in the past 30 days.¹⁹
You take a random sample of 15 undergraduates and ask them whether they
have received mean or hurtful comments online in the past 30 days. If the rate at
your university matches this 25% rate:
a. What is the distribution of the number of undergraduates who say that
they have received hurtful comments online in the past 30 days?
b. What is the distribution of the number of undergraduates who say that
they have not received hurtful comments online in the past 30 days?
c. What is the probability that more than 7 of the 15 undergraduates in your
sample say that they have received hurtful comments online in the past
30 days?
d. What is the probability that no more than 7 of the 15 students in your
sample say that they have not received hurtful comments online in the
past 30 days?

(5.33
p.320
ck: 15 (1) (4972) = 497.2 ⇒ binomial model is good,
a) X=# who have received mean comments, ~ (Bi(1525)
b) Y = # who haven't
~ Bi (15,75)
15) = ₂0393 +₁0131+.0034 +0007 +.0001 =
=60566
P(X>7) = P(8, 9, 10,
1
d) P(Y ≤ 7) = P(X) 17) =60566

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