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d. Q1 Q2 A charged ball with charge Q1 string as shown in the figure. The second charged ball has a net charge Q2 = -6 µC and it is located d = 0.4 m away from the suspended ball. (Note: The dashed horizontal line is not a string or rod, it only designates the distance d between the two spheres) = 5.9 µC and mass 0.6 kg is suspended from a ceiling with a thin massless What is the magnitude of the Electric Force between the two charged balls? Submit Answer Tries 0/2 What is the magnitude of the Gravitational Force on ball one? Submit Answer Tries 0/2 What is the magnitude of the tension in the x-direction? What is the magnitude of the tension in the y-direction? N. Submit Answer Tries 0/2 What is the angle e that the string makes with the vertical (dahsed vertical line) as shown in the figure? Provide your answer in degrees.

d. Q1 Q2 A charged ball with charge Q1 string as shown in the figure. The second charged ball has a net charge Q2 = -6 µC and it is located d = 0.4 m away from the suspended ball. (Note: The dashed horizontal line is not a string or rod, it only designates the distance d between the two spheres) = 5.9 µC and mass 0.6 kg is suspended from a ceiling with a thin massless What is the magnitude of the Electric Force between the two charged balls? Submit Answer Tries 0/2 What is the magnitude of the Gravitational Force on ball one? Submit Answer Tries 0/2 What is the magnitude of the tension in the x-direction? What is the magnitude of the tension in the y-direction? N. Submit Answer Tries 0/2 What is the angle e that the string makes with the vertical (dahsed vertical line) as shown in the figure? Provide your answer in degrees.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Q1 Q2 A charged ball with charge Q1 = 5.9 µC and mass 0.6 kg is suspended from a ceiling with a thin massless string as shown in the figure. The second charged ball has a net charge Q2 = -6 µC and it is located d = 0.4 m away from the suspended ball. (Note: The dashed horizontal line is not a string or rod, it only designates the distance d between the two spheres) %3D %3D What is the magnitude of the Electric Force between the two charged balls? Submit Answer Tries 0/2 What is the magnitude of the Gravitational Force on ball one? N. Submit Answer Tries 0/2 What is the magnitude of the tension in the x-direction? N. What is the magnitude of the tension in the y-direction? Submit Answer Tries 0/2 What is the angle e that the string makes with the vertical (dahsed vertical line) as shown in the figure? Provide your answer in degrees.
Transcribed Image Text:Q1 Q2 A charged ball with charge Q1 = 5.9 µC and mass 0.6 kg is suspended from a ceiling with a thin massless string as shown in the figure. The second charged ball has a net charge Q2 = -6 µC and it is located d = 0.4 m away from the suspended ball. (Note: The dashed horizontal line is not a string or rod, it only designates the distance d between the two spheres) %3D %3D What is the magnitude of the Electric Force between the two charged balls? Submit Answer Tries 0/2 What is the magnitude of the Gravitational Force on ball one? N. Submit Answer Tries 0/2 What is the magnitude of the tension in the x-direction? N. What is the magnitude of the tension in the y-direction? Submit Answer Tries 0/2 What is the angle e that the string makes with the vertical (dahsed vertical line) as shown in the figure? Provide your answer in degrees.
Expert Solution
Step 1

Given data

The magnitude of the charge on the first ball is Q1 = 5.9 μC = 5.9 x 10-6 C

The mass of the first ball is m1 = 0.6 kg

The magnitude of the charge on the second ball is Q2 = - 6 μC = - 6 x 10-6 C

The distance between the two balls is d = 0.4 m

 

The expression for the magnitude of the electric force between the two charged ball is given as:

Fe=kQ1Q2d2

Substitute the value in the above equation.

Fe=9×109 Nm2/C2×5.9×10-6 C×6×10-6 C0.4 m2Fe=1.991 N

Thus, the electric force between the charged ball is 1.991 N.

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