D. -my 4 JUD E. ans: E 53. The potential energy of a 0.20-kg particle moving along the axis is given by U(z) = (8.0 J/m²)x² + (2.0J/m*)x* . When the particle is at x = 1.0 m the magnitude of its acceleration is: A. 0 B. -8m/s C. 8m/s D. -40m/s E. 40 m/s UCI) = 10 W= -lo -lo-ma d 7) ans: D Chapter 8: POTENTIAL ENERGY AND CONSERVATION OF ENER

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Chapter1: Units, Trigonometry. And Vectors
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D.
E.
ans: E
53. The potential energy of a 0.20-kg particle moving along the axis is given by
U(z) = (8.0 J/m²)x² + (2.0J/m*)x .
When the particle is at x = 1.0 m the magnitude of its acceleration is:
UCI) = 10
W= -lo
-lo-ma d
A. 0
B. -8m/s
C. 8m/s
D. -40m/s
E. 40 m/s
ans: D
Chapter 8: POTENTIAL ENERGY AND CONSERVATION OF ENER
Transcribed Image Text:D. E. ans: E 53. The potential energy of a 0.20-kg particle moving along the axis is given by U(z) = (8.0 J/m²)x² + (2.0J/m*)x . When the particle is at x = 1.0 m the magnitude of its acceleration is: UCI) = 10 W= -lo -lo-ma d A. 0 B. -8m/s C. 8m/s D. -40m/s E. 40 m/s ans: D Chapter 8: POTENTIAL ENERGY AND CONSERVATION OF ENER
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