(d) You are told that o² = 1, 0₁ = 0.2 and 02 = -0.1 is the variance for the time series mean estimator less efficient or more efficient than the T = 20 sample size ensemble average i.i.d. case? Justify your answer with a relevant calculation and explanation using the formula in Equation (1) provided above in part (c) of this question.

(d) You are told that o² = 1, 0₁ = 0.2 and 02 = -0.1 is the variance for the time series mean estimator less efficient or more efficient than the T = 20 sample size ensemble average i.i.d. case? Justify your answer with a relevant calculation and explanation using the formula in Equation (1) provided above in part (c) of this question.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

1. A study compared the number of tree species in unlogged forest plots to similar plots logged 8 years earlier. Independent random samples of both logged and unlogged plots were analyzed and the number of tree species was recorded. Tables 1 and 2 present the Shapiro-Wilk normality test for both types of forest plots and the Independent Samples t-test results. Use the information presented in these tables to answer the questions. Table 1: Tests of Normality Tests of Normality Kolmogorov-Smirnov Shapiro-Wilk Forest Plot Statistic df Sig. Statistic df Sig. Tree_Species Logged .181 12 .200 .936 12 .444 Unlogged .110 14 .200 .945 14 .480 *. This is a lower bound of the true significance. a. Lilliefors Significance Correction Table 2: Independent Samples Test Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means 95% Confidence Interval of the Difference Mean Std. Error F Sig. t df Sig. (2-tailed) Difference Difference Lower Upper Equal variances…
I need the answer as soon as possible
2
Question 5 of 19 Compute the MSE for the following data. Period 1 2 3 4 5 6 13 Select the correct response. 12 11 Actual 492 470 485 493 498 492 14 Forecast (Error) 495 465 487 490 499 498 -5 -3 1 6 |Error] 3 LO 5 2 3 1 6 Error² 9 25 4 9 1 36 Error/Actual*100 0.60 1.06 0.41 0.60 0.20 1.21
12. The components of the OLS variances Under assumptions MLR.1 through MLR.5, conditional on the sample values of the independent variables, the variance of B; under OLS is: Var (B) sST, (1-15) where o2 = the variance of the error term SST; = the total sample variation of a; R; = the R-squared from a regression of r; on all of the other explanatory variables, along with an intercept parameter The variance of Bi v as R; increases. decreases For the given mode e following would lead to a reduction of the sampling variance of B;? increases O Adding variable that is equal to 5+ *j O Using the same data set with the same number of observations O Adding irrelevant explanatory variables to the model that are correlated with r; O Choosing an explanatory variable z that is uncorrelated with the other explanatory variables in the model
Let X-1: correct, X=0 : wrong And P= Pr(X=1)=2/5 What is the variance? .32 O.6 O .4
You may need to use the appropriate technology to answer this question. The following data are from a completely randomized design. In the following calculations, use a = 0.05. Treatment Treatment Treatment 3 64 82 69 47 71 53 54 87 60 35 64 46 50 76 57 148.67 108.67 96.67 (a) Use analysis of variance to test for a significant difference among the means of the three treatments.
Part A of question one asks for the variance (sigma squared), not the equation of regression line. Is the variance 2.79 as I listed on my answer sheet? Maybe my image didn't go through, but I already had the answer to subparts B and C to the question, which you list as #2 and #3. But I need help with parts D, E, and F. I have the following answers for D. d. Y hat (fitted value = 426.46), with residual of -1.62. e. r squared value = 1.00 g. 99% confidence interval = (-11.63, -1.05) Thanks thanks
I need this question completed in 10 minutes with full handwritten working out
5. (10) A recent Gallup Organization Poll asked male and female Americans whether they were pro or pro choice when it comes to abortion issues. The results of the survey are as follows: life Opinion Pro-Life Pro-Choice Gender Men 195 200 Women 240 250 Test whether an individual's opinion regarding abortion is independent of gender at the a = 0.025 level of significance.
6. What is the answer in (1) in the coefficients table?
1. A study compared the number of tree species in unlogged forest plots to similar plots logged 8 years earlier. Independent random samples of both logged and unlogged plots were analyzed and the number of tree species was recorded. Tables 1 and 2 present the Shapiro-Wilk normality test for both types of forest plots and the Independent Samples t-test results. Use the information presented in these tables to answer the questions. Table 1: Tests of Normality Tests of Normality Kolmogorov-Smirnov Shapiro-Wilk Forest Plot Statistic df Sig. Statistic df Sig. Tree_Species Logged .181 12 .200 .936 12 .444 Unlogged .110 14 .200 .945 14 .480 *. This is a lower bound of the true significance. a. Lilliefors Significance Correction Table 2: Independent Samples Test Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means 95% Confidence Interval of the Difference Mean Std. Error F Sig. t df Sig. (2-tailed) Difference Difference Lower Upper Equal variances…