E Solve the equation using the method of variation of parameters.d² ydx²a) d²ydx²c)e)d'ydx³d'ydx³- 4y = 5x-3d²ydx²d'y dy-2. +dx²dxd'y dydx+4y=e*g) +dx³=5x= sec x tan xb)d)f)d³ ydx³+9y = sec 3x,-79²)dx²d³ ydx³-3d²ydx²dy+14- -8y = ln xdx+3 dyf) dy-7d²ydx²-- y = 3e*dxdydx+14---8y = ln x, (0, 0)

Answered: Image /qna-images/answer/5088b27d-200a-4c21-8cee-c5f7ebbaa098.jpg

Answered: d³ y dx³ -2 d²y dy 202y dx² + = 5x dx

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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