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(d) Would you expect the proportion of stay-at-home residents to be higher in Virginia than in Arkansas? Support your conclusion with the results obtained in parts (b) and (c). From the results obtained in parts (b) and (c), we would expect the number of stay-at-home residents to be higher ✔✔✔in Arkansas than Virginia. The sample results show that, rounded to two decimal places, the estimated percentage of Arkansas residents who were born there is 2.08 x%. The sample results also show that, rounded to two decimal places, the estimated percentage of Virginia residents who were born there is 0.0372

(d) Would you expect the proportion of stay-at-home residents to be higher in Virginia than in Arkansas? Support your conclusion with the results obtained in parts (b) and (c). From the results obtained in parts (b) and (c), we would expect the number of stay-at-home residents to be higher ✔✔✔in Arkansas than Virginia. The sample results show that, rounded to two decimal places, the estimated percentage of Arkansas residents who were born there is 2.08 x%. The sample results also show that, rounded to two decimal places, the estimated percentage of Virginia residents who were born there is 0.0372

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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You may need to use the appropriate appendix table or technology to answer this question. What percentage of the population live in their state of birth? According to the U.S. Census Bureau's 2014 American Community Survey, the figure ranges from 25% in Nevada to 78.7% in Louisiana. The average percentage across all states and the District of Columbia is 57.7%. The data in the file HomeState are consistent with the findings in this American Community Survey. The data are for a random sample of 120 Arkansas residents and for a random sample of 180 Virginia residents. (a) Formulate hypotheses that can be used to determine whether the percentage of stay-at-home residents in the two states differs from the overall average of 57.7%. Ho: p > 0.577 Ha: p ≤ 0.577 Ho: p = 0.577 Ha: P = 0.577 Ho: p ≤ 0.577 Ha: p > 0.577 Ho: p≥ 0.577 Ha: p < 0.577 Ho: P < 0.577 Ha: p≥ 0.577 (b) Estimate the proportion of stay-at-home residents in Arkansas. (Round your answer to four decimal places.) 0.6167 Does this proportion differ significantly from the mean proportion for all states? Use a = 0.05. Find the value of the test statistic. (Round your answer to two decimal places.) 0.88 Find the p-value. (Round your answer to four decimal places.) p-value = 0.3788 What is your conclusion? Reject Ho. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. Do not reject Ho. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. Reject Ho. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. Do not reject Ho. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. (c) Estimate the proportion of stay-at-home residents in Virginia. (Round your answer to four decimal places.) 0.4944 Does this proportion differ significantly from the mean proportion for all states? Use a = 0.05. Find the value of the test statistic. (Round your answer to two decimal places.) -2.24
Transcribed Image Text:You may need to use the appropriate appendix table or technology to answer this question. What percentage of the population live in their state of birth? According to the U.S. Census Bureau's 2014 American Community Survey, the figure ranges from 25% in Nevada to 78.7% in Louisiana. The average percentage across all states and the District of Columbia is 57.7%. The data in the file HomeState are consistent with the findings in this American Community Survey. The data are for a random sample of 120 Arkansas residents and for a random sample of 180 Virginia residents. (a) Formulate hypotheses that can be used to determine whether the percentage of stay-at-home residents in the two states differs from the overall average of 57.7%. Ho: p > 0.577 Ha: p ≤ 0.577 Ho: p = 0.577 Ha: P = 0.577 Ho: p ≤ 0.577 Ha: p > 0.577 Ho: p≥ 0.577 Ha: p < 0.577 Ho: P < 0.577 Ha: p≥ 0.577 (b) Estimate the proportion of stay-at-home residents in Arkansas. (Round your answer to four decimal places.) 0.6167 Does this proportion differ significantly from the mean proportion for all states? Use a = 0.05. Find the value of the test statistic. (Round your answer to two decimal places.) 0.88 Find the p-value. (Round your answer to four decimal places.) p-value = 0.3788 What is your conclusion? Reject Ho. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. Do not reject Ho. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. Reject Ho. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. Do not reject Ho. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577. (c) Estimate the proportion of stay-at-home residents in Virginia. (Round your answer to four decimal places.) 0.4944 Does this proportion differ significantly from the mean proportion for all states? Use a = 0.05. Find the value of the test statistic. (Round your answer to two decimal places.) -2.24
(c) Estimate the proportion of stay-at-home residents in Virginia. (Round your answer to four decimal places.) 0.4944 Does this proportion differ significantly from the mean proportion for all states? Use a = 0.05. Find the value of the test statistic. (Round your answer to two decimal places.) -2.24 Find the p-value. (Round your answer to four decimal places.) p-value: = 0.0249 What is your conclusion? Reject Ho. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Do not reject Ho. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Reject Ho. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Do not reject Ho. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. (d) Would you expect the proportion of stay-at-home residents to be higher in Virginia than in Arkansas? Support your conclusion with the results obtained in parts (b) and (c). From the results obtained in parts (b) and (c), we would expect the number of stay-at-home residents to be higher there is 2.08 in Arkansas than Virginia. The sample results show that, rounded to two decimal places, the estimated percentage of Arkansas residents who were born %. %. The sample results also show that, rounded to two decimal places, the estimated percentage of Virginia residents who were born there is 0.0372
Transcribed Image Text:(c) Estimate the proportion of stay-at-home residents in Virginia. (Round your answer to four decimal places.) 0.4944 Does this proportion differ significantly from the mean proportion for all states? Use a = 0.05. Find the value of the test statistic. (Round your answer to two decimal places.) -2.24 Find the p-value. (Round your answer to four decimal places.) p-value: = 0.0249 What is your conclusion? Reject Ho. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Do not reject Ho. There is sufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Reject Ho. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Do not reject Ho. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. (d) Would you expect the proportion of stay-at-home residents to be higher in Virginia than in Arkansas? Support your conclusion with the results obtained in parts (b) and (c). From the results obtained in parts (b) and (c), we would expect the number of stay-at-home residents to be higher there is 2.08 in Arkansas than Virginia. The sample results show that, rounded to two decimal places, the estimated percentage of Arkansas residents who were born %. %. The sample results also show that, rounded to two decimal places, the estimated percentage of Virginia residents who were born there is 0.0372
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