(d) The student has just finished learning the first 30 percent of the words. (Give your answers correct to at least three decimal places) How long would it take to learn 30 percent of the remaining words? 714 hours After doing this, how long would it take to learn 30 percent of the words that then remain? x hours 0.178

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Help I cannot get the last question right

A student must learn Munfamiliar words for an upcoming test. The rate at which the student learms is proportional to the number of items remaining to be leamed, with constant of proportionality
equal to k. Initially, the student knows none of the words. Let y(t) stand for the number of the words that the student knows at time t
(a) Write down the right hand side of the differential equation satisfied by y. (Your answer should be given in terms of y.)
dy-K(M-y)
(b) What is the initial value of y? (Give an exact answer.)
(0) 0
(c) Suppose that there are 140 words to be learned and that 0.5 per hour for this student Recall that the solution to y-A(M-y) with y(0) 0 is given by v) M(1), (Give
your answers correct to at least three decimal places)
How many hours would it take the student to learn the first 30 percent of the words?
713
✓hours
How long would it take to learn the next 30 percent of the words?
1.12
✔hours
How long would it take to learn the next 30 percent of the words?
2.772
hours
(d) The student has just finished learning the first 30 percent of the words. (Give your answers correct to at least three decimal places.)
How long would it take to learn 30 percent of the remaining words?
714
✔hours
After doing this, how long would it take to learn 30 percent of the words that then remain?
0178
X hours
Transcribed Image Text:A student must learn Munfamiliar words for an upcoming test. The rate at which the student learms is proportional to the number of items remaining to be leamed, with constant of proportionality equal to k. Initially, the student knows none of the words. Let y(t) stand for the number of the words that the student knows at time t (a) Write down the right hand side of the differential equation satisfied by y. (Your answer should be given in terms of y.) dy-K(M-y) (b) What is the initial value of y? (Give an exact answer.) (0) 0 (c) Suppose that there are 140 words to be learned and that 0.5 per hour for this student Recall that the solution to y-A(M-y) with y(0) 0 is given by v) M(1), (Give your answers correct to at least three decimal places) How many hours would it take the student to learn the first 30 percent of the words? 713 ✓hours How long would it take to learn the next 30 percent of the words? 1.12 ✔hours How long would it take to learn the next 30 percent of the words? 2.772 hours (d) The student has just finished learning the first 30 percent of the words. (Give your answers correct to at least three decimal places.) How long would it take to learn 30 percent of the remaining words? 714 ✔hours After doing this, how long would it take to learn 30 percent of the words that then remain? 0178 X hours
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