d) Suppose the Jackson family use the following appliances on a typical day in October: Plasma TV (uses 250 watts per hour), used for 6 hours Microwave oven (uses 900 watts per hour), used for 30 minutes Refrigerator (uses 600 watts per hour), used for 24 hours Freezer (uses 400 watts per hour), used for 24 hours Determine how many kilowatts is used by these 4 appliances in a 31-day month. Round your final answer to the nearest tenth.

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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Understanding Electricity Charges: AEP Billing Explained**

American Electric Power (AEP) uses three types of charges to calculate a household's monthly electricity bill:

1. **Customer Charge**: This is a flat monthly rate (adjusted annually) charged to each household.

2. **Transmission Service Charge**: This charge covers the cost of moving electricity from power plants to substations and is based on the household's electricity usage.

3. **Distribution Service Charge**: This reflects the cost of distributing electricity from local substations to homes, also based on usage.

For this example, AEP's charges are:
- Customer charge: $8.40
- Transmission service: 2.93 cents per kWh
- Distribution service: 4.17 cents per kWh

**Scenario Analysis**

*a) September Billing for the Jackson Household*

Electricity used: 1,042 kWh

To calculate the bill:
- Customer charge: $8.40
- Transmission cost: \(2.93 \, \text{cents} \times 1042 \, \text{kWh} = \$30.54\)
- Distribution cost: \(4.17 \, \text{cents} \times 1042 \, \text{kWh} = \$43.44\)

Total September bill = $8.40 + $30.54 + $43.44 = **$82.38**

*b) August vs. July Usage Comparison for the Jackson Household*

In August, the household used 320 kWh more than in July.

Additional cost:
- Transmission cost increase: \(2.93 \, \text{cents} \times 320 \, \text{kWh} = \$9.38\)
- Distribution cost increase: \(4.17 \, \text{cents} \times 320 \, \text{kWh} = \$13.34\)

Total additional cost for August compared to July = \$9.38 + \$13.34 = **$22.72**

This illustrates how changes in electricity usage and rate changes affect billing.
Transcribed Image Text:**Understanding Electricity Charges: AEP Billing Explained** American Electric Power (AEP) uses three types of charges to calculate a household's monthly electricity bill: 1. **Customer Charge**: This is a flat monthly rate (adjusted annually) charged to each household. 2. **Transmission Service Charge**: This charge covers the cost of moving electricity from power plants to substations and is based on the household's electricity usage. 3. **Distribution Service Charge**: This reflects the cost of distributing electricity from local substations to homes, also based on usage. For this example, AEP's charges are: - Customer charge: $8.40 - Transmission service: 2.93 cents per kWh - Distribution service: 4.17 cents per kWh **Scenario Analysis** *a) September Billing for the Jackson Household* Electricity used: 1,042 kWh To calculate the bill: - Customer charge: $8.40 - Transmission cost: \(2.93 \, \text{cents} \times 1042 \, \text{kWh} = \$30.54\) - Distribution cost: \(4.17 \, \text{cents} \times 1042 \, \text{kWh} = \$43.44\) Total September bill = $8.40 + $30.54 + $43.44 = **$82.38** *b) August vs. July Usage Comparison for the Jackson Household* In August, the household used 320 kWh more than in July. Additional cost: - Transmission cost increase: \(2.93 \, \text{cents} \times 320 \, \text{kWh} = \$9.38\) - Distribution cost increase: \(4.17 \, \text{cents} \times 320 \, \text{kWh} = \$13.34\) Total additional cost for August compared to July = \$9.38 + \$13.34 = **$22.72** This illustrates how changes in electricity usage and rate changes affect billing.
**Text Transcription for Educational Website:**

---

**c)** We know that 1 kilowatt = 1,000 watts. Suppose that on Wednesday a plasma TV that uses 250 watts per hour is kept on for 6 hours, and a dishwasher that uses 1800 watts per hour is used for 2 hours. How many *kilowatts* were used by these two appliances on Wednesday?

**Calculations:**

- *Plasma TV* - 250 watts per hour for 6 hours  
- *Dishwasher* - 1800 watts per hour for 2 hours

\[ 
(250 \times 6) + (1800 \times 2) = 1500 + 3600 = 5100 \text{ watts} 
\]

Convert watts to kilowatts:

\[ 
5100 \div 1000 = 5.1 \text{ kilowatts} 
\]

There were 5.1 kilowatts used on Wednesday.

---

**d)** Suppose the Jackson family use the following appliances on a typical day in October:

- **Plasma TV** (uses 250 watts per hour), used for 6 hours
- **Microwave oven** (uses 900 watts per hour), used for 30 minutes
- **Refrigerator** (uses 600 watts per hour), used for 24 hours
- **Freezer** (uses 400 watts per hour), used for 24 hours

*Determine how many kilowatts is used by these 4 appliances in a 31-day month. Round your final answer to the nearest tenth.*

---
Transcribed Image Text:**Text Transcription for Educational Website:** --- **c)** We know that 1 kilowatt = 1,000 watts. Suppose that on Wednesday a plasma TV that uses 250 watts per hour is kept on for 6 hours, and a dishwasher that uses 1800 watts per hour is used for 2 hours. How many *kilowatts* were used by these two appliances on Wednesday? **Calculations:** - *Plasma TV* - 250 watts per hour for 6 hours - *Dishwasher* - 1800 watts per hour for 2 hours \[ (250 \times 6) + (1800 \times 2) = 1500 + 3600 = 5100 \text{ watts} \] Convert watts to kilowatts: \[ 5100 \div 1000 = 5.1 \text{ kilowatts} \] There were 5.1 kilowatts used on Wednesday. --- **d)** Suppose the Jackson family use the following appliances on a typical day in October: - **Plasma TV** (uses 250 watts per hour), used for 6 hours - **Microwave oven** (uses 900 watts per hour), used for 30 minutes - **Refrigerator** (uses 600 watts per hour), used for 24 hours - **Freezer** (uses 400 watts per hour), used for 24 hours *Determine how many kilowatts is used by these 4 appliances in a 31-day month. Round your final answer to the nearest tenth.* ---
Expert Solution
Step 1

The relation between kilowatt and watt is 

as follows :

                1 kilowatt = 1000 watt .

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