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(d) Suppose that the sample standard deviation was s = 5.4. Compute a 98% confidence interval for u, the mean time spent volunteering for the population of parents of school-aged children (Round your answers to three decimal places.) Interpret a 98% confidence interval for u, the mean time spent volunteering for the population of parents of school-aged children. We are 98% confident that the median time spent volunteering for the population of parents of school age children is between these two values. We are 98% confident that the mean time spent volunteering for the population of parents of school age children is between these two values. We are 98% confident that the true mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. There is a 98% chance that the true mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. There is a 98% chance that the true difference in the mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values.

(d) Suppose that the sample standard deviation was s = 5.4. Compute a 98% confidence interval for u, the mean time spent volunteering for the population of parents of school-aged children (Round your answers to three decimal places.) Interpret a 98% confidence interval for u, the mean time spent volunteering for the population of parents of school-aged children. We are 98% confident that the median time spent volunteering for the population of parents of school age children is between these two values. We are 98% confident that the mean time spent volunteering for the population of parents of school age children is between these two values. We are 98% confident that the true mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. There is a 98% chance that the true mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. There is a 98% chance that the true difference in the mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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In a survey, the sample consisted of 1087 adults who were parents of school-aged children. The sample was selected in a way that makes it reasonable to regard it as representative of the population of parents of school-aged children. One question on the survey asked respondents how much time (in hours) per month they spent volunteering at their children's school during the previous school year. The following summary statistics for time volunteered per month are given below. n = 1087 x = 5.5 median = 1
Transcribed Image Text:In a survey, the sample consisted of 1087 adults who were parents of school-aged children. The sample was selected in a way that makes it reasonable to regard it as representative of the population of parents of school-aged children. One question on the survey asked respondents how much time (in hours) per month they spent volunteering at their children's school during the previous school year. The following summary statistics for time volunteered per month are given below. n = 1087 x = 5.5 median = 1
(d) Suppose that the sample standard deviation was s = 5.4. Compute a 98% confidence interval for u, the mean time spent volunteering for the population of parents of school-aged children. (Round your answers to three decimal places.) Interpret a 98% confidence interval for u, the mean time spent volunteering for the population of parents of school-aged children. We are 98% confident that the median time spent volunteering for the population of parents of school age children is between these two values. We are 98% confident that the mean time spent volunteering for the population of parents of school age children is between these two values. We are 98% confident that the true mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. There is a 98% chance that the true mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. O There is a 98% chance that the true difference in the mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. O O O O
Transcribed Image Text:(d) Suppose that the sample standard deviation was s = 5.4. Compute a 98% confidence interval for u, the mean time spent volunteering for the population of parents of school-aged children. (Round your answers to three decimal places.) Interpret a 98% confidence interval for u, the mean time spent volunteering for the population of parents of school-aged children. We are 98% confident that the median time spent volunteering for the population of parents of school age children is between these two values. We are 98% confident that the mean time spent volunteering for the population of parents of school age children is between these two values. We are 98% confident that the true mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. There is a 98% chance that the true mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. O There is a 98% chance that the true difference in the mean time spent volunteering for the population of parents of school age children is directly in the middle of these two values. O O O O
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