d) Solve 32x 5 (mod 51).
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter6: Fractions
Section6.1: Simplifying Fractions
Problem 31WE
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![Solve each of the following modular arithmetic equations, giving your answer as a set of all possible solutions in the given modulus.
If there are no solutions, enter set().
If there is one solution, say 1, enter set (1).
If there are multiple solutions, say 1 and 2, enter set (1,2).
When evaluating in modulo m, give each answer in its lowest non-negative form - that is, as an element of {0, 1, 2,..., m - 1}.
a)
Solve 260x = 20 (mod 404).
b)
Solve 425x = 4 (mod 1802).
c)
Solve 222x = 18 (mod 612).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F640887de-34e2-4fb5-a217-028aef2f5eb9%2Fd986e6d1-9bee-4142-8548-a76f2e68c6bf%2Feie2jef_processed.png&w=3840&q=75)
Transcribed Image Text:Solve each of the following modular arithmetic equations, giving your answer as a set of all possible solutions in the given modulus.
If there are no solutions, enter set().
If there is one solution, say 1, enter set (1).
If there are multiple solutions, say 1 and 2, enter set (1,2).
When evaluating in modulo m, give each answer in its lowest non-negative form - that is, as an element of {0, 1, 2,..., m - 1}.
a)
Solve 260x = 20 (mod 404).
b)
Solve 425x = 4 (mod 1802).
c)
Solve 222x = 18 (mod 612).
![d)
Solve 32x = 5 (mod 51).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F640887de-34e2-4fb5-a217-028aef2f5eb9%2Fd986e6d1-9bee-4142-8548-a76f2e68c6bf%2Fvqezys_processed.png&w=3840&q=75)
Transcribed Image Text:d)
Solve 32x = 5 (mod 51).
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