D Question 5 Calculate the test statistic. Ot- 1.75 Ot-.0.9624
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Chapter1: Combinatorial Analysis
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![Question 5
Calculate the test statistic.
Ot- 1.75
Ot--0.9624
Ot--0.9213
O t- 0,9624
Ot-0.9213
Ot- 2.13
Question 6
State your hypotheses.
O Ho : 100 vs H, :u« 100
O Ho: u- 100 vs HA :H 100
O Ha: u- 100 vs Ha: u> 100
O Hạ:p- 100 vs H :p > 100
O H3: 4; - u; - 0 vs HA : H; - H; <0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f06213d-bcc2-4045-ad90-8caf2f6bc73e%2F792f6421-ff6f-4902-8ce6-8e7918b10bd2%2F8akpurv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 5
Calculate the test statistic.
Ot- 1.75
Ot--0.9624
Ot--0.9213
O t- 0,9624
Ot-0.9213
Ot- 2.13
Question 6
State your hypotheses.
O Ho : 100 vs H, :u« 100
O Ho: u- 100 vs HA :H 100
O Ha: u- 100 vs Ha: u> 100
O Hạ:p- 100 vs H :p > 100
O H3: 4; - u; - 0 vs HA : H; - H; <0
![A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCi/L of radon (1 pCi is one trillionth of a
Curie). The resulting readings were as follows:
105.6
90.9
91.2
96.9
96.5
91.3.
100.1
105
99.6 107.7
103.3
92.4
Does this data suggest that the population mean reading under these conditions differs from 100? State and test the appropriate
hypotheses using alpha = 0.05.
Question 4
Determine the critical value/s. Choose the best answer.
O lalpha = 0.025. df - 11) = 2.201
O talpha - 0.025, df = 11) = + 2.201
O t lalpha = 0.05, df - 11) = : 2.201
O lalpha = 0.05, df - 12) = + 2.201
O lalpha = 0.05, df - 11) - - 2.201](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f06213d-bcc2-4045-ad90-8caf2f6bc73e%2F792f6421-ff6f-4902-8ce6-8e7918b10bd2%2Fd1ancpa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCi/L of radon (1 pCi is one trillionth of a
Curie). The resulting readings were as follows:
105.6
90.9
91.2
96.9
96.5
91.3.
100.1
105
99.6 107.7
103.3
92.4
Does this data suggest that the population mean reading under these conditions differs from 100? State and test the appropriate
hypotheses using alpha = 0.05.
Question 4
Determine the critical value/s. Choose the best answer.
O lalpha = 0.025. df - 11) = 2.201
O talpha - 0.025, df = 11) = + 2.201
O t lalpha = 0.05, df - 11) = : 2.201
O lalpha = 0.05, df - 12) = + 2.201
O lalpha = 0.05, df - 11) - - 2.201
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