(d) Look carefully at your drawing above. In what direction does E point (inward? outward? tangent?) at various locations on the Gaussian surface? Redraw your Gaussian surface below and draw short arrows on the surface indicating the direction of E on the Gaussian surface. +Q• (e) Consider the following argument from a student who is trying to detemine E somewhere on the previous Gaussian surface: "The total charge enclosed by the surface is zero. According to Gauss’ law this means the total electric field flux through the surface is zero. Therefore, the electric field is zero everywhere on the surface." Which, if any, of the three sentences are correct? Explain how the student came to an incorrect conclusion.

(d) Look carefully at your drawing above. In what direction does E point (inward? outward? tangent?) at various locations on the Gaussian surface? Redraw your Gaussian surface below and draw short arrows on the surface indicating the direction of E on the Gaussian surface. +Q• (e) Consider the following argument from a student who is trying to detemine E somewhere on the previous Gaussian surface: "The total charge enclosed by the surface is zero. According to Gauss’ law this means the total electric field flux through the surface is zero. Therefore, the electric field is zero everywhere on the surface." Which, if any, of the three sentences are correct? Explain how the student came to an incorrect conclusion.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Implementing Gauss's law on a cylinder. You're going to find the electric field at a point P due to a cylinder made of an insulating material. Again, we'll assume an infinitely long cylinder, although you can consider a section with finite length L, and radius R. Let P be a distance "D" away from the central axis of the cylinder, which has a charge density p. Make sure to keep D and R straight, in terms of which you are using where. The drawing can help. 1. Draw a suitable Gaussian surface on the picture below. P L 2. Add vectors for då of the gaussian surface, (the infinitesimal area elements) on the drawing. 3. Draw vectors for the electric field caused by L on the Gaussian surface. 4. Write down an equation for p. Plug in to a geometrical equation so that it is in terms of given variables. 5. Write down Gauss's law, and use # 4 to substitute on one side. 6. Simplify the other side of Gauss's law based on the geometry of what you did in #2 and #3. 7. Use an equation for the surface…
Calculate the electric field at height h above the center of a square plate of size 2a×2a with uniform surface charge density η (both direction and magnitude). Verify that in the limit of large a the result agrees with the field of an infinite uniformly charged plane.
We have calculated the electric field due to a uniformly charged disk of radius R, along its axis. Note that the final result does not contain the integration variable r: R. Q/A 2€0 Edisk (x² +R*)* Edisk perpendicular to the center of the disk Uniform Q over area A (A=RR²) Show that at a perpendicular distance R from the center of a uniformly negatively charged disk of CA and is directed toward the disk: Q/A radius R, the electric field is 0.3- 2€0 4.4.1b
Please show your clean and complete solution. Thanks
A Gaussian surface in the form of a hemisphere of radius r lies in a uniform electric field of magnitude E. The surface encloses no net charge. At the (flat) base of the surface, the field is perpendicular to the surface and directed into the surface. NOTE: Express your answers in terms of the given variables, using when needed. (a) What is the flux through the base of the surface? Φ (b) What is the flux through the curved portion of the surface? Φ =
Consider the following image, point P is located on the x axis with coordinates (X, 0). Two positive charged particles are on the y-axis, ad and b apart respectively from the point of origin (0, 0). Draw each component of the electric field at point P?
A proton is held stationary at distance d, from an infinitely large conducting plane (sheet) of charge with uniform charge density -o. It is then released and moves straight towards the plane. Find the speed of the proton when it is at distance d, from the plane. The electric field of the plane is uniform everywhere in space and has the magnitude E = Ignore the gravitational force. Present your answer symbolically.
Find the electric flux through a single side of regular octahedron of the side a 4cm with the charge 180 nC placed at the geometric centre of it. Take k to be 8.99x10° N/C. Give your answer to the nearest tenth of Nm2/C. Your Answer:
A spherical conducting shell with outer radius 8 meters carries total charge Q2 of -6 Coulombs. Inside the shell cavity is an object carrying total charge Q1 of 1 Coulombs. What is the total charge on the inner surface of the conducting shell? Make sure to give the proper sign.(Note that you are not being asked the total charge of the entire shell.) Assume equilibrium. Hint: What is the electric field inside any conductor at equilibrium? Use Gauss's Law to determine the charge. Make sure to choose your Gaussian surface so it is useful for deducing the charge on the inner surface of the shell.
Gaussian surface 1 has twice the area ofGaussian surface 2. Both surfaces enclose the same charge Q.(a) Is the electric flux through surface 1 greater than, less than, orthe same as the electric flux through surface 2? (b) Choose the bestexplanation from among the following:I. Gaussian surface 2 is closer to the charge, since it has thesmaller area. It follows that it has the greater electric flux.II. The two surfaces enclose the same charge, and hence theyhave the same electric flux.III. Electric flux is proportional to area. As a result, Gaussian surface 1 has the greater electric flux
Gaussian surface 1 has twice the area of Gaussian surface 2. Both surfaces enclose the same charge Q. Is the electric flux through surface 1 greater than, less than, or the same as the electric flux through surface 2?
The figure below represents the top view of a cubic gaussian surface in a uniform electric field E oriented parallel to the top and bottom faces of the cube. The field makes an angle with side 1, and the area of each face is A. (Use any variable or symbol stated above along with the following as necessary: E for the magnitude of the electric field.) (a) In symbolic form, find the electric flux through face 1. ΦΕ = (b) In symbolic form, find the electric flux through in 2. ΦΕ = (c) In symbolic form, find the electric flux through face 3. ΦΕ = (d) In symbolic form, find the electric flux through face 4. ΦΕ (e) In symbolic form, find the electric flux through the top and bottom faces of the cube. E E 1 = top bottom = = = (f) What is the net electric flux through the cube? ΦΕ (g) How much charge is enclosed within the gaussian surface? 9 in