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(d) Let A be a 4 × 5 matrix. Then the column vectors of A are linearly dependent. True False Justification: (e) If u is in span{v, w} then u is in span{v+w, w − v} True False Justification: (f) let A, B be two matrices. If (A - B)² = A² − 2AB + B², then AB = BA. True False Justification: (g) If A and B are symmetric matrices, then AB is a symmetric matrix. True False Justification:

(d) Let A be a 4 × 5 matrix. Then the column vectors of A are linearly dependent. True False Justification: (e) If u is in span{v, w} then u is in span{v+w, w − v} True False Justification: (f) let A, B be two matrices. If (A - B)² = A² − 2AB + B², then AB = BA. True False Justification: (g) If A and B are symmetric matrices, then AB is a symmetric matrix. True False Justification:

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please justifiy using math

(d) Let A be a 4 × 5 matrix. Then the column vectors of A are linearly dependent. True False Justification: (e) If u is in span{v, w} then u is in span{v+w, w − v} True False Justification: (f) let A, B be two matrices. If (A - B)² = A² − 2AB + B², then AB = BA. True False Justification: (g) If A and B are symmetric matrices, then AB is a symmetric matrix. True False Justification:
Transcribed Image Text:(d) Let A be a 4 × 5 matrix. Then the column vectors of A are linearly dependent. True False Justification: (e) If u is in span{v, w} then u is in span{v+w, w − v} True False Justification: (f) let A, B be two matrices. If (A - B)² = A² − 2AB + B², then AB = BA. True False Justification: (g) If A and B are symmetric matrices, then AB is a symmetric matrix. True False Justification:
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