Assingnment 1 Question #6.Answer Part D Only!!! **Standard Normal Distribution Table (Page 1)****Diagram Explanation:**- The diagram illustrates a standard normal distribution curve with a shaded area representing the probability for a given z-score.**Table:**- The table lists z-scores ranging from -3.4 to 0.4. - Each row corresponds to a z-score value, and each column provides the cumulative probability for the standard normal distribution at varying decimal places. **Example:**- For z = -3.0 and a decimal of 0.04, the cumulative probability is 0.0006.---**Standard Normal Distribution Table (Page 2)****Diagram Explanation:**- Similar diagram as page 1, representing the standard normal distribution with a highlighted area under the curve.**Table:**- The table lists z-scores from 0.0 to 3.8.- It provides cumulative probabilities for each z-score with varying decimals.**Example:**- For z = 1.3 and a decimal of 0.06, the cumulative probability is 0.9032.This table is used to find the probability that a statistic is observed below, above, or in between standard deviations from the mean in a standard normal distribution. A random sample of 1,026 adults in a certain large country was asked, "Do you pretty much think televisions are a necessity or a luxury you could do without?" Of the 1,026 adults surveyed, 515 indicated that televisions are a luxury they could do without. Links:- Click here to view the standard normal distribution table (page 1).- Click here to view the standard normal distribution table (page 2).(a) Obtain a point estimate for the population proportion of adults in the country who believe that televisions are a luxury they could do without.\(\hat{p} = 0.502\)(Round to three decimal places as needed.)(b) Verify that the requirements for constructing a confidence interval about \( p \) are satisfied.The sample is \(\text{stated to be}\) a simple random sample, the value of \( n\hat{p}(1-\hat{p}) \) is \( 256.496 \), which is \(\text{greater than or equal to}\) 10, and the \(\text{sample size}\) \(\text{can be assumed to be}\) less than or equal to 5% of the population size.(Round to three decimal places as needed.)(c) Construct and interpret a 95% confidence interval for the population proportion of adults in the country who believe that televisions are a luxury they could do without. Select the correct choice below and fill in any answer boxes within your choice.(Type integers or decimals rounded to three decimal places as needed. Use ascending order.)A. We are \(95\%\) confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between \(0.471\) and \(0.533\).B. There is a \(\%\) probability the proportion of adults in the country who believe that televisions are a luxury they could do without is between \([blank]\) and \([blank]\).(d) Is it possible that a supermajority (more than 60%) of adults in the country believe that television is a luxury they could do without? Is it likely?It is \([blank]\) that a supermajority of adults in the country believe that television is a luxury they could do without because the 95% confidence interval \([blank]\).(Type an integer or a decimal. Do not round.)

The 95% confidence interval is given by (0.471, 0.533)d) Since all values in the confidence interval (0.471, 0.533) are less than 60% = 0.60, then there is not enough evidence to say that more than 60% of adults in the country believe that televisions are a luxury they could do without it. So the answer is It is not possible to believe that a supermajority of adults in the country believe that television is a luxury they could do without because the 95% confidence interval contains values less than 0.60.