(d) ires = 0: for index1 = 10:-2:1 for index2 = 2:2: indexl if index2 - 6 break lend res + index2: ies end number of times (outer loop) number of times (inner loop)
(d) ires = 0: for index1 = 10:-2:1 for index2 = 2:2: indexl if index2 - 6 break lend res + index2: ies end number of times (outer loop) number of times (inner loop)
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter5: Control Structures Ii (repetition)
Section: Chapter Questions
Problem 31SA
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Question
![(d)
ires = 0;
for index1 = 10:-2:1
for index2 = 2:2: indexl
if index2 = 6
creak
end
ires = res + index2;
end
end
number of times (outer loop)
number of times (inner loop)
R](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f9495af-9934-40ca-9d15-b346fcb38054%2Ff2ae3ffe-1ad6-414c-90b5-6ae8b27fda98%2Fyoyc0qs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(d)
ires = 0;
for index1 = 10:-2:1
for index2 = 2:2: indexl
if index2 = 6
creak
end
ires = res + index2;
end
end
number of times (outer loop)
number of times (inner loop)
R
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