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(d) How far horizontally from the base of the building does the ball strike the ground? m (e) Find the height from which the ball was thrown. m (f) How long does it take the ball to reach a point 10.0 m below the level of launching?

(d) How far horizontally from the base of the building does the ball strike the ground? m (e) Find the height from which the ball was thrown. m (f) How long does it take the ball to reach a point 10.0 m below the level of launching?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Physics Problems: Projectile Motion #### Problem Set ###### (d) **Question:** How far horizontally from the base of the building does the ball strike the ground? **Answer:** \[ \_\_\_\_\_\_\_\_ \text{m} \] ###### (e) **Question:** Find the height from which the ball was thrown. **Answer:** \[ \_\_\_\_\_\_\_\_ \text{m} \] ###### (f) **Question:** How long does it take the ball to reach a point 10.0 m below the level of launching? **Answer:** \[ \_\_\_\_\_\_\_\_ \text{s} \] --- *Follow the calculations and principles of projectile motion to solve these problems. Remember to consider the effects of gravity, initial velocity, and angles of projection.*
Transcribed Image Text:### Physics Problems: Projectile Motion #### Problem Set ###### (d) **Question:** How far horizontally from the base of the building does the ball strike the ground? **Answer:** \[ \_\_\_\_\_\_\_\_ \text{m} \] ###### (e) **Question:** Find the height from which the ball was thrown. **Answer:** \[ \_\_\_\_\_\_\_\_ \text{m} \] ###### (f) **Question:** How long does it take the ball to reach a point 10.0 m below the level of launching? **Answer:** \[ \_\_\_\_\_\_\_\_ \text{s} \] --- *Follow the calculations and principles of projectile motion to solve these problems. Remember to consider the effects of gravity, initial velocity, and angles of projection.*
### Physics Problem: Projectile Motion From the window of a building, a ball is tossed from a height \( y_0 \) above the ground with an initial velocity of **8.10 m/s** and an angle of **21.0°** below the horizontal. It strikes the ground **6.00 s** later. --- In this scenario, the ball undergoes projectile motion, influenced by gravity, affecting both its vertical and horizontal components of motion. Notice the given parameters: - Initial velocity (\( v_0 \)) = **8.10 m/s** - Angle of projection \( (\theta) \) = **21.0° below the horizontal** - Time of flight (t) = **6.00 s** To solve for various parameters such as the range, maximum height, or the final velocity upon impact, we would need to decompose the initial velocity into horizontal and vertical components and apply the kinematic equations. --- #### Key Concepts: - **Vertical Motion**: Governed by the acceleration due to gravity (9.8 m/s²). - **Horizontal Motion**: Constant velocity as there’s no horizontal acceleration (assuming negligible air resistance). The details given, help in understanding the dynamics and the subsequent calculations which can include determining the height of the window (\( y_0 \)), the range (\( x \)), and the final velocity components just before the ball strikes the ground.
Transcribed Image Text:### Physics Problem: Projectile Motion From the window of a building, a ball is tossed from a height \( y_0 \) above the ground with an initial velocity of **8.10 m/s** and an angle of **21.0°** below the horizontal. It strikes the ground **6.00 s** later. --- In this scenario, the ball undergoes projectile motion, influenced by gravity, affecting both its vertical and horizontal components of motion. Notice the given parameters: - Initial velocity (\( v_0 \)) = **8.10 m/s** - Angle of projection \( (\theta) \) = **21.0° below the horizontal** - Time of flight (t) = **6.00 s** To solve for various parameters such as the range, maximum height, or the final velocity upon impact, we would need to decompose the initial velocity into horizontal and vertical components and apply the kinematic equations. --- #### Key Concepts: - **Vertical Motion**: Governed by the acceleration due to gravity (9.8 m/s²). - **Horizontal Motion**: Constant velocity as there’s no horizontal acceleration (assuming negligible air resistance). The details given, help in understanding the dynamics and the subsequent calculations which can include determining the height of the window (\( y_0 \)), the range (\( x \)), and the final velocity components just before the ball strikes the ground.
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