(d) H B M → (i) Show that OD = (2-2)a+2b. (ii) Hence show that OD: DB = 2:1 A +1 Not to Scale In the diagram, side OA of AOAB is produced to C so that AC=OA. Mis the midpoint →>> of AB and CM produced meets OB in D. OA=a, OB = b and CD= CM for some parameter 2.
(d) H B M → (i) Show that OD = (2-2)a+2b. (ii) Hence show that OD: DB = 2:1 A +1 Not to Scale In the diagram, side OA of AOAB is produced to C so that AC=OA. Mis the midpoint →>> of AB and CM produced meets OB in D. OA=a, OB = b and CD= CM for some parameter 2.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question

Transcribed Image Text:(d)
D
H
B
M
(1) Show that OD = (2-32) g + 12b.
(ii) Hence show that OD: DB = 2:1
A
#
Not to Scale
C
In the diagram, side OA of AOAB is produced to C so that AC = OA. M is the midpoint
→
of AB and CM produced meets OB in D. OA= a, OB = b and CD= CM for some
parameter 2.
Expert Solution

Step 1
For this problem, we have to use the triangular law of vector addition and the vector section formula.
Triangular law of vector addition:
The triangle law of vector addition says that when two vectors are represented as two sides of a triangle with the same order of magnitude and direction, then the magnitude and direction of the resultant vector is represented by the third side of the triangle taken in reverse order.
In the above diagram, we have .
If a point divides the line joining in the ratio , then,
.
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