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(d) f(x) = log3 (6x − 1) - ln(6x - 1) + 4eª − e¹x - 1 a logb

(d) f(x) = log3 (6x − 1) - ln(6x - 1) + 4eª − e¹x - 1 a logb

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Part d. 
f(x) = log3(6x-1) + 4ex-e4x

(d) f(x) = log3(6x – 1) – ln(6x – 1) + 4e² - est 1 f(x) = - a logb
Transcribed Image Text:(d) f(x) = log3(6x – 1) – ln(6x – 1) + 4e² - est 1 f(x) = - a logb
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