d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10 SUV Va Soom Vb 1000 ^ 200 + IT ix 100 τον t 200- ①Short circuit 750 2000-1 40000 №2 (900 зл Ra = + 200 = 1900 ~ 3 RT = t 1900 3 R+ = It= 200 2522 VT RT By COR: = 400 1 + 100 -1 + 500 SO = 0·19841 252 inx= 100 × 0.19841 200+100 i3 (T-1x=11 ix = 0.06614 0.19841 -0.06614 = 0.13227 100 75 152 7 1₁ =a.13227 13 500 iz Consider 15V source; 1700/3 ~ iz IT 200-n 400-2 t 75V 100 00 eT = (i 1700 + 400 IT = VT -1 +200 -434.46 75 RT 434.48 I = I + I2 200 400 IT 200♫ - + 750 13 = M 100 1527100 x 0.17262 13 = 0.0685 =0·17262A 12 = 400 1700 x0.0685 +400 = 18227 +0.0283 = 0.0283 =0·161 X

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Please answer the following using the superposition theorem. I have attempted to answer, but I do not know where I have gone wrong. Please correct my mistakes and answer the question with the same method I have used  

The correct answer to the question is 0.0238A from A to B

d) For the circuit shown in figure Q3d use the superposition principle to find the
current through the 500 2 resistor.
50 V
+
100 Ω
75 V
+
200 Ω
400 Ω
200 Ω
Figure Q3d
500 Ω
10
Transcribed Image Text:d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10
SUV
Va
Soom Vb
1000
^
200
+
IT
ix
100
τον
t
200-
①Short circuit 750
2000-1
40000
№2
(900
зл
Ra =
+
200
=
1900
~
3
RT =
t
1900
3
R+
=
It=
200
2522
VT
RT
By COR:
=
400
1
+ 100
-1
+ 500
SO
= 0·19841
252
inx=
100
× 0.19841
200+100
i3
(T-1x=11
ix = 0.06614
0.19841 -0.06614 = 0.13227
100
75
152
7
1₁ =a.13227
13
500
iz
Consider 15V source;
1700/3 ~
iz
IT
200-n
400-2
t
75V
100
00
eT =
(i
1700
+
400
IT = VT
-1
+200
-434.46
75
RT 434.48
I = I + I2
200
400
IT
200♫
-
+
750
13 =
M
100
1527100
x 0.17262
13 = 0.0685
=0·17262A
12 =
400
1700
x0.0685
+400
= 18227 +0.0283
= 0.0283
=0·161 X
Transcribed Image Text:SUV Va Soom Vb 1000 ^ 200 + IT ix 100 τον t 200- ①Short circuit 750 2000-1 40000 №2 (900 зл Ra = + 200 = 1900 ~ 3 RT = t 1900 3 R+ = It= 200 2522 VT RT By COR: = 400 1 + 100 -1 + 500 SO = 0·19841 252 inx= 100 × 0.19841 200+100 i3 (T-1x=11 ix = 0.06614 0.19841 -0.06614 = 0.13227 100 75 152 7 1₁ =a.13227 13 500 iz Consider 15V source; 1700/3 ~ iz IT 200-n 400-2 t 75V 100 00 eT = (i 1700 + 400 IT = VT -1 +200 -434.46 75 RT 434.48 I = I + I2 200 400 IT 200♫ - + 750 13 = M 100 1527100 x 0.17262 13 = 0.0685 =0·17262A 12 = 400 1700 x0.0685 +400 = 18227 +0.0283 = 0.0283 =0·161 X
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