Need answer of part d,e fast Stepla)The moment of inertia of an object rotating about an axis ofrotation is given asI = mr²m is the mass of the objectr is the dis tan ce of the object from the axis of rotationIn the given problem, there are three particles lying on a rod, atdistances y=-4 m, y=-2 m and =3 mThese particles have masses 3, 2 and 4 kg respectively. This rod,with the particles, rotates about the x axis with an angular speedof 2.6 rad/sThe total moment of inertia of this rotating rod will be the sum ofthe moment of inertia of all the three particles rotating about thefixed x axisStep2b)Thus,I = m¡r,² + mzr2² + mzrz²I = 3(-4)° + 2(–2)² + 4(3)²I = 92 kg m²And for this total moment of inertia of the rod, the total rotationalkinetic energy of the rod isK =w = 2.6 rad/sK = × 92 × (2.6)²K = 310. 96 JStep3c)The tangential velocity of a rotating object is given asThus, for each of the 3 masses,VAkg = 3 x 2. 6VAkg = 7. 8 m/sVzkg = 2 x 2. 6V2kg5. 2 m/sVzka = 4 x 2. 6Vykg = 10. 4 m/sStep4d)Since we only answer up to 3 sub-parts, we'll answer the first 3.Please resubmit the question and specify the other subparts (upto 3) you'd like answered. Rigid rods of negligible mass lying along the y axis connect three particles. The system rotates about the x axis with an angularspeed of 2.60 rad/s.4.00 kgy = 3.00 m2.00 kg Oy=-2.00 m3.00 kg (y = -4.00 m(a) Find the moment of inertia about the x axis.kg - m2(b) Find the total rotational kinetic energy evaluated from to?.(c) Find the tangential speed of each particle.4.00 kg particle2.00 kg particle3.00 kg particlem/sm/sm/s(d) Find the total kinetic energy evaluated from !mv?.(e) Compare the answers for kinetic energy in parts (b) and (d).

The rod located along the y axis houses 3 particles of masses 4, 2 and 3 kg, at distances 3, -2 and…

Answered: (d) Find the total kinetic energy…

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(d) Find the total kinetic energy evaluated from m. .Σ (e) Compare the answers for kinetic energy in parts (b) and (d).