(d) Find the ideal inlet temperature for the production of styrene for a steam/ethylbenzene ratio of 58:1. (Hint: Plot the molar flow rate of styrene versus TO. Explain why your curve looks the way it does.)
(d) Find the ideal inlet temperature for the production of styrene for a steam/ethylbenzene ratio of 58:1. (Hint: Plot the molar flow rate of styrene versus TO. Explain why your curve looks the way it does.)
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![(Comprehensive Problem on multiple reactions with heat effects) Styrene can be produced
from ethylbenzene by the following reaction:
ethylbenzene + styrene + H2 (1)
However, several irreversible side reactions also occur:
ethylbenzene – benzene + ethylene (2)
ethylbenzene + H2 → toluene 4- methane (3)
[J. Snyder and B. Subramaniam, Chem. Eng. Sci., 49, 5585 (1994)]. Ethylbenzene is fed at a
rate of 0.00344 kmol/s to a 10.0-m3 PFR (PBR) along with inert steam at a total pressure of
2.4 atm. The steam/ethylbenzene molar ratio is initially [ie., parts (a) to (C)] 14.5:1 but can be
varied. Given the following data, find the exiting molar flow rates of styrene, benzene, and
toluene along with 5'si/bt for the following inlet temperatures when the reactor is operated
adiabatically.
(a) TO = 800 K
(b) TO = 930 K
(C) TO = 1100 K
(d) Find the ideal inlet temperature for the production of styrene for a steam/ethylbenzene ratio
of 58:1. (Hint: Plot the molar flow rate of styrene versus TO. Explain why your cunrve looks the
way it does.)
(e) Find the ideal steam/ethylbenzene ratio for the production of styrene at 900 K [Hint: See
part (d).J
(f) It is proposed to add a counter current heat exchanger with Ua = 100 kJ/m3/min/K where Ta
is virtually constant at 1000 K. For an entering steam to ethylbenzene ratio of 20, what would
you suggest as an entering temperature? Plot the molar flow rates and S'sv/bt.
(9) What do you believe to be the points of this problem?
(h) Ask another question or suggest another calculation that can be made for this problem.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F881981d6-3e02-4e67-b4bd-0ffa6ec9cc32%2F065a9721-429a-47a5-9fc9-da5e0b969e24%2F5v66crt_processed.png&w=3840&q=75)
Transcribed Image Text:(Comprehensive Problem on multiple reactions with heat effects) Styrene can be produced
from ethylbenzene by the following reaction:
ethylbenzene + styrene + H2 (1)
However, several irreversible side reactions also occur:
ethylbenzene – benzene + ethylene (2)
ethylbenzene + H2 → toluene 4- methane (3)
[J. Snyder and B. Subramaniam, Chem. Eng. Sci., 49, 5585 (1994)]. Ethylbenzene is fed at a
rate of 0.00344 kmol/s to a 10.0-m3 PFR (PBR) along with inert steam at a total pressure of
2.4 atm. The steam/ethylbenzene molar ratio is initially [ie., parts (a) to (C)] 14.5:1 but can be
varied. Given the following data, find the exiting molar flow rates of styrene, benzene, and
toluene along with 5'si/bt for the following inlet temperatures when the reactor is operated
adiabatically.
(a) TO = 800 K
(b) TO = 930 K
(C) TO = 1100 K
(d) Find the ideal inlet temperature for the production of styrene for a steam/ethylbenzene ratio
of 58:1. (Hint: Plot the molar flow rate of styrene versus TO. Explain why your cunrve looks the
way it does.)
(e) Find the ideal steam/ethylbenzene ratio for the production of styrene at 900 K [Hint: See
part (d).J
(f) It is proposed to add a counter current heat exchanger with Ua = 100 kJ/m3/min/K where Ta
is virtually constant at 1000 K. For an entering steam to ethylbenzene ratio of 20, what would
you suggest as an entering temperature? Plot the molar flow rates and S'sv/bt.
(9) What do you believe to be the points of this problem?
(h) Ask another question or suggest another calculation that can be made for this problem.
![Heat capacities
Methane 68 J/mol · K
Styrene
273 J/nol·K
Ethylbenzene 299 J/nol ·K
30 J/mɔl · K
40 J/mɔl · K
Ethylene 90 J/mol · K
Benzene 201 J/mol·K
Hydrogen
Toluene 249 J/mol·K
Steam
p = 2137 kg/m³ of pellet
o = 0.4
AHaIEB = 118,000 kJ/kmol ethylbenzene
AHRx2EB
105,200 kJ/kmol ethylbenzene
AHRJEB = -53,900 kJ/kmol ethylbenzene
b2
Kp = exp{b, ++b, In (T')+ [(b,T+b;)T+ b,]"} atm
b, = -17.34
b, = -2.314 X 10-10
bz = -1.302X 104
b, = 1.302 X 10-5
%3D
bz = 5.051
b6
= -4.931 X 10-3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F881981d6-3e02-4e67-b4bd-0ffa6ec9cc32%2F065a9721-429a-47a5-9fc9-da5e0b969e24%2Fo0sfjx_processed.png&w=3840&q=75)
Transcribed Image Text:Heat capacities
Methane 68 J/mol · K
Styrene
273 J/nol·K
Ethylbenzene 299 J/nol ·K
30 J/mɔl · K
40 J/mɔl · K
Ethylene 90 J/mol · K
Benzene 201 J/mol·K
Hydrogen
Toluene 249 J/mol·K
Steam
p = 2137 kg/m³ of pellet
o = 0.4
AHaIEB = 118,000 kJ/kmol ethylbenzene
AHRx2EB
105,200 kJ/kmol ethylbenzene
AHRJEB = -53,900 kJ/kmol ethylbenzene
b2
Kp = exp{b, ++b, In (T')+ [(b,T+b;)T+ b,]"} atm
b, = -17.34
b, = -2.314 X 10-10
bz = -1.302X 104
b, = 1.302 X 10-5
%3D
bz = 5.051
b6
= -4.931 X 10-3
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