d²µ dx2 + K2»(x) = 0 2mE V K = ħ 2
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![d²p
+ K²µ(x)= 0
dx2
2mE
K=V
ħ 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F39600fef-21bb-45d4-8e3c-4c1081d02621%2F84bdc58e-bfa2-401e-a56e-c18abff063de%2Fjo7my1_processed.jpeg&w=3840&q=75)
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