d dx sin(t) dt

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Instructions say to find the first derivative.

The image shows a mathematical expression involving differentiation and integration. The expression is:

\[ 
\frac{d}{dx} \int_{0}^{x^2} \sin(t) \, dt 
\]

This expression represents the derivative with respect to \( x \) of the integral of \( \sin(t) \) with respect to \( t \) from 0 to \( x^2 \).

### Key Components:
1. **Integral**:
   \[
   \int_{0}^{x^2} \sin(t) \, dt
   \]
   This is a definite integral where the function \( \sin(t) \) is integrated with respect to \( t \) from 0 to \( x^2 \).

2. **Derivative**:
   \[
   \frac{d}{dx}
   \]
   This indicates taking the derivative of the integral with respect to \( x \).

### Explanation:
- The inner part:
  \[
  \int_{0}^{x^2} \sin(t) \, dt
  \]
  results in a value that depends on \( x^2 \), and thus on \( x \).
  
- The derivative:
  \[
  \frac{d}{dx}
  \]
  acts on this value. Essentially, this problem involves the method of differentiation under the integral sign, often referred to as the Leibniz rule or the Fundamental Theorem of Calculus when dealing with variable limits of integration.

### Step-by-Step Solution:
1. **Substitute and Differentiate**: According to the Leibniz rule, if we have \( \int_{a(x)}^{b(x)} f(t) \, dt \), then:
   \[
   \frac{d}{dx} \int_{a(x)}^{b(x)} f(t) \, dt = f(b(x)) \cdot b'(x) - f(a(x)) \cdot a'(x)
   \]
   
2. **Apply to our integral**:
   Here, \( a(x) = 0 \) and \( b(x) = x^2 \), so:
   \[
   \frac{d}{dx} \int_{0}^{x^2} \sin(t) \, dt = \sin(x^2) \cdot \frac{d}{dx} (x^2) - \sin(0) \cdot
Transcribed Image Text:The image shows a mathematical expression involving differentiation and integration. The expression is: \[ \frac{d}{dx} \int_{0}^{x^2} \sin(t) \, dt \] This expression represents the derivative with respect to \( x \) of the integral of \( \sin(t) \) with respect to \( t \) from 0 to \( x^2 \). ### Key Components: 1. **Integral**: \[ \int_{0}^{x^2} \sin(t) \, dt \] This is a definite integral where the function \( \sin(t) \) is integrated with respect to \( t \) from 0 to \( x^2 \). 2. **Derivative**: \[ \frac{d}{dx} \] This indicates taking the derivative of the integral with respect to \( x \). ### Explanation: - The inner part: \[ \int_{0}^{x^2} \sin(t) \, dt \] results in a value that depends on \( x^2 \), and thus on \( x \). - The derivative: \[ \frac{d}{dx} \] acts on this value. Essentially, this problem involves the method of differentiation under the integral sign, often referred to as the Leibniz rule or the Fundamental Theorem of Calculus when dealing with variable limits of integration. ### Step-by-Step Solution: 1. **Substitute and Differentiate**: According to the Leibniz rule, if we have \( \int_{a(x)}^{b(x)} f(t) \, dt \), then: \[ \frac{d}{dx} \int_{a(x)}^{b(x)} f(t) \, dt = f(b(x)) \cdot b'(x) - f(a(x)) \cdot a'(x) \] 2. **Apply to our integral**: Here, \( a(x) = 0 \) and \( b(x) = x^2 \), so: \[ \frac{d}{dx} \int_{0}^{x^2} \sin(t) \, dt = \sin(x^2) \cdot \frac{d}{dx} (x^2) - \sin(0) \cdot
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