d Calculater₁(t) · r₂(t)] and [r₁(t) × r2(t)] first by differentiating dt the product directly and then by applying the formulas d. dr₂ dr₁ ==[r₁(t) · r2(t)] = r₁(t) · + r₂(t) and dt dt dt d dr₂ dr₁ [r₁(t) × r₂(t)] = r₁(t) × + x r₂(t). dt dt dt r₁(t) = cos(t)i + sin(t)j + 5tk, r₂(t) = 4i + tk d [r₁(t) · r2(t)] 10 t - 4 sin(t) ✓ = dt d [r₁(t) × r2(t)] : = (t cos(t) + sin(t)) i + (t cos(t) − cos(t) +20) j − 4 cos(t) k X dt .

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 20E
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please help me correct the following

Your answer is partially correct.
d
d
Calculate [ri(t) r₂(t)] and[r₁(t) × r₂(t)] first by differentiating
·
dt
dt
the product directly and then by applying the formulas
d
dr2 dri
[r₁(t) · r₂(t)] = r₁(t) · +
r₂(t) and
dt
dt dt
d
dr₂ dri
[r₁(t) × r₂(t)] = r₁(t) × + x r₂(t).
dt
dt dt
r₁(t) = cos(t)i + sin(t)j + 5tk, r₂(t) = 4i + tk
d
[r₁(t) · r₂(t)] =
=
10 t - 4 sin(t)
dt
d
[r₁(t) × r₂(t)] = [(t cos(t) + sin(t)) i + (t cos(t) − cos(t) +20) j — 4 cos(t) k
X
dt
.
Transcribed Image Text:Your answer is partially correct. d d Calculate [ri(t) r₂(t)] and[r₁(t) × r₂(t)] first by differentiating · dt dt the product directly and then by applying the formulas d dr2 dri [r₁(t) · r₂(t)] = r₁(t) · + r₂(t) and dt dt dt d dr₂ dri [r₁(t) × r₂(t)] = r₁(t) × + x r₂(t). dt dt dt r₁(t) = cos(t)i + sin(t)j + 5tk, r₂(t) = 4i + tk d [r₁(t) · r₂(t)] = = 10 t - 4 sin(t) dt d [r₁(t) × r₂(t)] = [(t cos(t) + sin(t)) i + (t cos(t) − cos(t) +20) j — 4 cos(t) k X dt .
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