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d) cosec ² (x) dy = sec (4) dx -cos (2x) Ssin²(x) dx = -1/2/1-Cos(2x) dx -1/2 (X-1/2 Sin(2x))+C dy (=) (cy) = Date: ax CS(²(X) = <= cos(y) dy - Sin² (x) dx [cos(y)dy = fsin² (x) dx/ sinly) = sin(2x) + + +C y = -si =-Sin`^ (sin(x) cos(x)=-2X + C)

d) cosec ² (x) dy = sec (4) dx -cos (2x) Ssin²(x) dx = -1/2/1-Cos(2x) dx -1/2 (X-1/2 Sin(2x))+C dy (=) (cy) = Date: ax CS(²(X) = <= cos(y) dy - Sin² (x) dx [cos(y)dy = fsin² (x) dx/ sinly) = sin(2x) + + +C y = -si =-Sin`^ (sin(x) cos(x)=-2X + C)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Attached you'll find my solution for the seperable ODE "csc^2(x)dy = sec(y)dx". Is it correct? 

वप d) cosec² (x) dy = sec (y) dx = sec (y) dx (=) sally Secty Ssin ²(x) dx = √² M-COS(2x) 2 dx -1/2 √1-Cos(2x) dx = 1/2 (X-1/2 Sin(2x))+ ( Date: ax CS(²(X) y = - 1 1 (=) cos(y) dy = Sin² (x) dx [cosly) dy jsin² (x) dx/ sinly) = + X+C 4 -Sin^ (sin(x) cos(x³=2X + C) 4
Transcribed Image Text:वप d) cosec² (x) dy = sec (y) dx = sec (y) dx (=) sally Secty Ssin ²(x) dx = √² M-COS(2x) 2 dx -1/2 √1-Cos(2x) dx = 1/2 (X-1/2 Sin(2x))+ ( Date: ax CS(²(X) y = - 1 1 (=) cos(y) dy = Sin² (x) dx [cosly) dy jsin² (x) dx/ sinly) = + X+C 4 -Sin^ (sin(x) cos(x³=2X + C) 4
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