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d) Compare these three answers. You should have found that the probability that the average IQ is 106 or higher decreases as n increases. Explain why.

d) Compare these three answers. You should have found that the probability that the average IQ is 106 or higher decreases as n increases. Explain why.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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hi can you answer D answers for a,b, and c are there thank you
3. IQ scores are normally distributed with a mean of µ = 100 and a standard deviation of o = 15. a) What is the probability that a single (n = 1) randomly selected person has an IQ of at least 106? b) Now suppose that a random sample of n = 9 people take the IQ test. What is the probability that the average IQ score of those 9 people is 106 or above? c) Repeat part (b) with n = 25 as the sample size. d) Compare these three answers. You should have found that the probability that the average IQ is 106 or higher decreases as n increases. Explain why.
Transcribed Image Text:3. IQ scores are normally distributed with a mean of µ = 100 and a standard deviation of o = 15. a) What is the probability that a single (n = 1) randomly selected person has an IQ of at least 106? b) Now suppose that a random sample of n = 9 people take the IQ test. What is the probability that the average IQ score of those 9 people is 106 or above? c) Repeat part (b) with n = 25 as the sample size. d) Compare these three answers. You should have found that the probability that the average IQ is 106 or higher decreases as n increases. Explain why.
9 P(X >106)= P( X-4> 106 -100) 15 - PlZ>0.4) :0:3446 P(x 2106) = 0.·3446 りn-9 106-100) 15/N9 P(X >106) = P( X - - P(ZzI·2) :0·1151 P(ã Z 106) = 0-1l151 C) n= 25 P( 8 ? (06) = P( メ-リ 106-100 へ - P(zz 2)=0.0228 Plă>106) =0-0228 = 0-0228
Transcribed Image Text:9 P(X >106)= P( X-4> 106 -100) 15 - PlZ>0.4) :0:3446 P(x 2106) = 0.·3446 りn-9 106-100) 15/N9 P(X >106) = P( X - - P(ZzI·2) :0·1151 P(ã Z 106) = 0-1l151 C) n= 25 P( 8 ? (06) = P( メ-リ 106-100 へ - P(zz 2)=0.0228 Plă>106) =0-0228 = 0-0228
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