d Calculate[ri(t) · r2(t)] and 77[r1(t) × r2(t)] first by differentiating @[r₁(t) the product directly and then by applying the formulas d dr₂ dri . [r₁(t) · r₂(t)] = r₁(t) · + · r₂(t) and dt dt dt d dr2 dr₁ [r₁(t) × r₂(t)] = r₁(t) × + x r₂(t). dt dt dt r₁(t) = cos(t)i + sin(t)j + 2tk, r₂(t) = i + tk d. [r₁(t) · ri(t) r₂(t)] -4 t - sin(t) = dt d -[r₁(t) × r₂(t)] = (sin(t) + t cos(t)) i+t sin(t) — cos(t) + 2 − cos(t) k dt
d Calculate[ri(t) · r2(t)] and 77[r1(t) × r2(t)] first by differentiating @[r₁(t) the product directly and then by applying the formulas d dr₂ dri . [r₁(t) · r₂(t)] = r₁(t) · + · r₂(t) and dt dt dt d dr2 dr₁ [r₁(t) × r₂(t)] = r₁(t) × + x r₂(t). dt dt dt r₁(t) = cos(t)i + sin(t)j + 2tk, r₂(t) = i + tk d. [r₁(t) · ri(t) r₂(t)] -4 t - sin(t) = dt d -[r₁(t) × r₂(t)] = (sin(t) + t cos(t)) i+t sin(t) — cos(t) + 2 − cos(t) k dt
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 27E
Related questions
Question
![Your answer is partially correct.
d
d
Calculate[ri(t) ·
[r₁(t) · r2(t)] and @[r₁(t) × r2(t)] first by differentiating
the product directly and then by applying the formulas
dr₂ dr₁
[r₁(t) · r₂(t)] = r₁(t) · +
r₂(t) and
dt
dt
dt
d
dr2 dr₁
-[r₁(t) × r₂(t)] = r₁(t) × + x r₂(t).
dt
dt
dt
r₁(t) = cos(t)i + sin(t)j + 2tk, r₂(t) = i + tk
d
[r₁(t) · r₂(t)]
4 t - sin(t)
dt
d
[r₁(t) × r₂(t)] = (sin(t) +t cos(t)) i + t sin(t) − cos(t) + 2 − cos(t) k
dt
=
.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7efc449-e5d0-4912-9b60-e847ba043df5%2F6cfecfb8-96a5-482c-b34f-f0b517895b50%2Fdwtrqe8_processed.png&w=3840&q=75)
Transcribed Image Text:Your answer is partially correct.
d
d
Calculate[ri(t) ·
[r₁(t) · r2(t)] and @[r₁(t) × r2(t)] first by differentiating
the product directly and then by applying the formulas
dr₂ dr₁
[r₁(t) · r₂(t)] = r₁(t) · +
r₂(t) and
dt
dt
dt
d
dr2 dr₁
-[r₁(t) × r₂(t)] = r₁(t) × + x r₂(t).
dt
dt
dt
r₁(t) = cos(t)i + sin(t)j + 2tk, r₂(t) = i + tk
d
[r₁(t) · r₂(t)]
4 t - sin(t)
dt
d
[r₁(t) × r₂(t)] = (sin(t) +t cos(t)) i + t sin(t) − cos(t) + 2 − cos(t) k
dt
=
.
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