(d) Calculate the magnitude (in m/s?) and direction (in degrees above or below the hor
(d) Calculate the magnitude (in m/s?) and direction (in degrees above or below the hor
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![A pendulum with a cord of length r = 1.05 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions 0 = 90° and 0 = 270°, its speed is 4.95 m/s.
a
(a) Find the magnitude of the radial acceleration (in m/s2) for these positions.
m/s2
(b) Find the magnitude of the tangential acceleration (in m/s?) for these positions.
m/s?
(c)
Draw a vector diagram to determine the direction of the total acceleration for these two positions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5e44bbd-96fc-4c8d-94dc-0f55891dee87%2Fffeabfc0-d9cc-4898-9a47-5f33b44f8e60%2F5sf44ng_processed.png&w=3840&q=75)
Transcribed Image Text:A pendulum with a cord of length r = 1.05 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions 0 = 90° and 0 = 270°, its speed is 4.95 m/s.
a
(a) Find the magnitude of the radial acceleration (in m/s2) for these positions.
m/s2
(b) Find the magnitude of the tangential acceleration (in m/s?) for these positions.
m/s?
(c)
Draw a vector diagram to determine the direction of the total acceleration for these two positions.
![at
at
a-
ar
at
ar
à
à
a,
0 = 90°
0 = 270°
e = 90 °
0 = 270°
0 = 90°
e = 270
a,
8 = 90°
e = 270°
(d) Calculate the magnitude (in m/s2) and direction (in degrees above or below the horizontal) of the total acceleration.
magnitude
m/s?
direction
O --Select--- •
the horizontal](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5e44bbd-96fc-4c8d-94dc-0f55891dee87%2Fffeabfc0-d9cc-4898-9a47-5f33b44f8e60%2Fz1s2xcw_processed.png&w=3840&q=75)
Transcribed Image Text:at
at
a-
ar
at
ar
à
à
a,
0 = 90°
0 = 270°
e = 90 °
0 = 270°
0 = 90°
e = 270
a,
8 = 90°
e = 270°
(d) Calculate the magnitude (in m/s2) and direction (in degrees above or below the horizontal) of the total acceleration.
magnitude
m/s?
direction
O --Select--- •
the horizontal
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