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[ [ d) calculate the ball’s path angle at the wall (negative angle cw from +x)]

[ [ d) calculate the ball’s path angle at the wall (negative angle cw from +x)]

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 0.020 kg paintball is launched 12 m/s , oriented 22° above +x , toward a wall 9.0 m away.
Transcribed Image Text:A 0.020 kg paintball is launched 12 m/s , oriented 22° above +x , toward a wall 9.0 m away.
[ d) calculate the ball's path angle at the wall (negative angle cw from +x) ] +2.635 m above launch height -10.641 m (below) launch height +6.842 m above launch height +3.636 m above launch height -2.776 m (below) launch height +0.430 m above launch height +12.422 m above launch height -3.432 m (below) launch height
Transcribed Image Text:[ d) calculate the ball's path angle at the wall (negative angle cw from +x) ] +2.635 m above launch height -10.641 m (below) launch height +6.842 m above launch height +3.636 m above launch height -2.776 m (below) launch height +0.430 m above launch height +12.422 m above launch height -3.432 m (below) launch height
Expert Solution
Step 1

Solution:

Calculate the maximum vertical height attained by the paintball.

H=u2sin2θ2g

Here, u is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.

H=122sin2222×9.8=144×0.1419.6=1.02857m

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