(b) Give a point estimate of a. (Round your answer to five decimal places.) Interpret this estimate. s is the typical amount by which the -Select-- regression line. ] value -Select-- ]what is predicted using the least squares (c) Give an estimate of the average change in depression score change associated with a 1 kg/m? increase in BMI change. (Round your answer to three decimal places.)

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Question
A paper gives data on x = change in Body Mass Index (BMI, in kilograms/meter) and y = change in a measure of depression for
patients suffering from depression who participated in a pulmonary rehabilitation program. The table below contains a subset of the
data given in the paper and are approximate values read from a scatterplot in the paper.
BMI Change (kg/m²)
1 1.5
1.1| 1 0.2 0.2
0.5 -0.5 0 0.1 0.7 0.8
Depression Score Change -1
4
4.
6
13
14
17
18
12
14
The accompanying computer output is from Minitab.
Fitted Line Plot
Depression score change = 7.200 + 4.789 BMI change
e =7.
20
5.38756
21.90%
R-Sq
R-Sq (adj) 14.09%
15-
10
-0.5
0.0
0.5
1.0
1.5
BMI change
R-aq
5.38756
21.904
Coefficienta
Term
Coef
Sz Coef
7-Value
P-Value
Vir
Constant
7.200
2.21
3.26
0.0086
BMI change
4.789
2.86
1.67
0.1249
1.00
Regression Equation
Depression score change = 7.200 + 4.789 BMI change
(a) What percentage of observed variation in depression score change can be explained by the simple linear regression model?
(Round your answer to two decimal places.)
Depression score change
Transcribed Image Text:A paper gives data on x = change in Body Mass Index (BMI, in kilograms/meter) and y = change in a measure of depression for patients suffering from depression who participated in a pulmonary rehabilitation program. The table below contains a subset of the data given in the paper and are approximate values read from a scatterplot in the paper. BMI Change (kg/m²) 1 1.5 1.1| 1 0.2 0.2 0.5 -0.5 0 0.1 0.7 0.8 Depression Score Change -1 4 4. 6 13 14 17 18 12 14 The accompanying computer output is from Minitab. Fitted Line Plot Depression score change = 7.200 + 4.789 BMI change e =7. 20 5.38756 21.90% R-Sq R-Sq (adj) 14.09% 15- 10 -0.5 0.0 0.5 1.0 1.5 BMI change R-aq 5.38756 21.904 Coefficienta Term Coef Sz Coef 7-Value P-Value Vir Constant 7.200 2.21 3.26 0.0086 BMI change 4.789 2.86 1.67 0.1249 1.00 Regression Equation Depression score change = 7.200 + 4.789 BMI change (a) What percentage of observed variation in depression score change can be explained by the simple linear regression model? (Round your answer to two decimal places.) Depression score change
(b) Give a point estimate of o. (Round your answer to five decimal places.)
Interpret this estimate.
s is the typical amount by which the -Select--
value -Select-
]what is predicted using the least squares
regression line.
(c) Give an estimate of the average change in depression score change associated with a 1 kg/m? increase in BMI change. (Round
your answer to three decimal places.)
(d) Calculate a point estimate of the mean depression score change for a patient whose BMI change was 1.2 kg/m². (Round your
answer to three decimal places.)
Transcribed Image Text:(b) Give a point estimate of o. (Round your answer to five decimal places.) Interpret this estimate. s is the typical amount by which the -Select-- value -Select- ]what is predicted using the least squares regression line. (c) Give an estimate of the average change in depression score change associated with a 1 kg/m? increase in BMI change. (Round your answer to three decimal places.) (d) Calculate a point estimate of the mean depression score change for a patient whose BMI change was 1.2 kg/m². (Round your answer to three decimal places.)
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(d) Calculate a point estimate of the mean depression score change for a patient whose BMI change was 1.2 kg/m2. (Round your
answer to three decimal places.)
Transcribed Image Text:(d) Calculate a point estimate of the mean depression score change for a patient whose BMI change was 1.2 kg/m2. (Round your answer to three decimal places.)
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