d) an — — 4 аn-1 + 2n + 3, ао

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 3RE
icon
Related questions
Topic Video
Question
To solve the recurrence relation given the initial conditions, use an iterative approach similar to the method used in Example 10.

d) \( a_n = a_{n-1} + 2n + 3, a_0 = 4 \)

(Insert iterative solution here)
Transcribed Image Text:To solve the recurrence relation given the initial conditions, use an iterative approach similar to the method used in Example 10. d) \( a_n = a_{n-1} + 2n + 3, a_0 = 4 \) (Insert iterative solution here)
**Problem 31:** What is the value of each of these sums of terms of a geometric progression?

### d) \(\sum_{j=0}^{8} 2 \cdot (-3)^j\)

In this problem, we are asked to find the value of the sum of the first 9 terms (from \( j = 0 \) to \( j = 8 \)) of a geometric progression, where each term is given by \( 2 \cdot (-3)^j \).

To find the value of this series, we can use the formula for the sum of the first \( n \) terms of a geometric progression:

\[ S_n = a \cdot \frac{1 - r^n}{1 - r} \]

Where:
- \( S_n \) is the sum of the first \( n \) terms.
- \( a \) is the first term of the progression.
- \( r \) is the common ratio.
- \( n \) is the number of terms.

For this series:
- \( a = 2 \) (the first term when \( j = 0 \)).
- \( r = -3 \) (the common ratio).
- The series has 9 terms (\( n = 9 \)).

Therefore, substituting these values into the formula:

\[ S_9 = 2 \cdot \frac{1 - (-3)^9}{1 - (-3)} \]

\[ S_9 = 2 \cdot \frac{1 - (-19683)}{1 + 3} \]

\[ S_9 = 2 \cdot \frac{1 + 19683}{4} \]

\[ S_9 = 2 \cdot \frac{19684}{4} \]

\[ S_9 = 2 \cdot 4921 \]

\[ S_9 = 9842 \]

Thus, the value of the sum of the given geometric progression is **9842**.
Transcribed Image Text:**Problem 31:** What is the value of each of these sums of terms of a geometric progression? ### d) \(\sum_{j=0}^{8} 2 \cdot (-3)^j\) In this problem, we are asked to find the value of the sum of the first 9 terms (from \( j = 0 \) to \( j = 8 \)) of a geometric progression, where each term is given by \( 2 \cdot (-3)^j \). To find the value of this series, we can use the formula for the sum of the first \( n \) terms of a geometric progression: \[ S_n = a \cdot \frac{1 - r^n}{1 - r} \] Where: - \( S_n \) is the sum of the first \( n \) terms. - \( a \) is the first term of the progression. - \( r \) is the common ratio. - \( n \) is the number of terms. For this series: - \( a = 2 \) (the first term when \( j = 0 \)). - \( r = -3 \) (the common ratio). - The series has 9 terms (\( n = 9 \)). Therefore, substituting these values into the formula: \[ S_9 = 2 \cdot \frac{1 - (-3)^9}{1 - (-3)} \] \[ S_9 = 2 \cdot \frac{1 - (-19683)}{1 + 3} \] \[ S_9 = 2 \cdot \frac{1 + 19683}{4} \] \[ S_9 = 2 \cdot \frac{19684}{4} \] \[ S_9 = 2 \cdot 4921 \] \[ S_9 = 9842 \] Thus, the value of the sum of the given geometric progression is **9842**.
Expert Solution
steps

Step by step

Solved in 2 steps with 4 images

Blurred answer
Knowledge Booster
Permutation and Combination
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage