a Ihe ExpertA Macmillan L XW SOCC ECON XM Inbox (2) - a X b My Question X X Mathway S XHB One-Sample x ttable.pdfOttable.pdf Xusn39or.theexpertta.com/Common/TakeTutorialAssignment.aspxClass ManagementTHeipCh 8: Momentum Begin Date: 11/1/2020 12:01:00 AM -- Due Date: 11/16/2020 11:59:00 PM End Date: 11/27/2020 11:59:00 PM(7%) Problem 7: A car moving at 10.5 m/s crashes into a tree and stops in 0.22 s.tusus50% Part (a) Calculate the magnitude of the force, in newtons, the seatbelt exerts on a passenger in the car to bring him to a halt. The mass of thepassenger is 72.5 kg.Grade SummaryDeductionsF=0%Potential100%sin()cos()tan()8.9.HOMESubmissions4Attempts remaining: 5(49% per attempt)detailed viewcotan()asin()acos()Eatan()acotan()sinh()23cosh()tanh()cotanh()ENDO Degrees O RadiansVOLBACESPACESubmitHintFeedbackI give up!Hints: 3% deduction per hint. Hints remaining:1Feedback: 296 deduction perfeedback.50% Part (b) What would the final velocity be, in meters per second, if the car with the 72.5-kg passenger had collided with (and stuck to) a car that hasan equal mass and is traveling in the opposite direction and at the same speed?All content 2020 Expert TA LLC3:36 PMW11/10/2020文

Given data The velocity of the car is u = 10.5 m/s. The time taken by the car to stop is ∆t=0.22 s The mass of the passenger is m = 72.5 kg. a) The force exerted by the person is calculated by the second law of motion as, F=maF=m×∆v∆t As the rate of change of velocity is known as acceleration, therefore, putting the values as, F=m×v-u∆tF=72.5 kg×0-10.5 m/s0.22 sF=3460.22 N Thus, the force exerted on the person is 3460.22 N. b) The final velocity of the passenger after the collision with the car having the same mass travelling in the opposite direction is calculated as, m1v1+m2v2=m1+m2vv=m1v1+m2v2m1+m2v=72.5 kg10.5 m/s+72.5 kg-10.5 m/s72.5 kg+72.5 kgv=0 m/s Thus, the final velocity after the collision is 0 m/s that is both the cars after the collision will become stationary.

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D A 50% Part (a) Calculate the magnitude of the force, in newtons, the seatbelt exerts on a passenger in the car to bring him to a halt. The mass of the passenger is 72.5 kg. Grade Summary F = Deductions Potential 100% sin() cos() tan() 17 HOME Submissions E 4 Attempts remaining: 5 (49% per attempt) detailed view cotan() asin() acos() 5 atan() acotan() sinh() 2 3 cosh() tanh() cotanh() END O Degrees O Radians VO BACKSPACE CLEAR Submit Hint Feedback I give up! Hints: 39% deduction per hint Hints remaining: 1 Feedback: 2% deduction per feedback E A 50% Part (b) What would the final velocity be, in meters per second, if the car with the 72.5-kg passenger had collided with (and stuck to) a car that has an equal mass and is traveling in the opposite direction and at the same speed? All content C2020 Espert TA. LLC

D A 50% Part (a) Calculate the magnitude of the force, in newtons, the seatbelt exerts on a passenger in the car to bring him to a halt. The mass of the passenger is 72.5 kg. Grade Summary F = Deductions Potential 100% sin() cos() tan() 17 HOME Submissions E 4 Attempts remaining: 5 (49% per attempt) detailed view cotan() asin() acos() 5 atan() acotan() sinh() 2 3 cosh() tanh() cotanh() END O Degrees O Radians VO BACKSPACE CLEAR Submit Hint Feedback I give up! Hints: 39% deduction per hint Hints remaining: 1 Feedback: 2% deduction per feedback E A 50% Part (b) What would the final velocity be, in meters per second, if the car with the 72.5-kg passenger had collided with (and stuck to) a car that has an equal mass and is traveling in the opposite direction and at the same speed? All content C2020 Espert TA. LLC

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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